Answered: I used the equation (x + 1)2 + (y - 5)2…

College Algebra (MindTap Course List)

12th Edition

ISBN:9781305652231

Author:R. David Gustafson, Jeff Hughes

Publisher:R. David Gustafson, Jeff Hughes

Chapter2: Functions And Graphs

Section2.5: Graphs Of Equations And Circles

Problem 89E

See similar textbooks

Related questions

Question

I used the equation (x + 1)² + (y - 5)² = -4 to identify the circle’s center and radius.Determine whether the statement makes sense or does not make sense, and explain your reasoning.

Expert Solution

Step 1

The standard equation of a circle is given as:

${(x - h)}^{2} + {(y - k)}^{2} = r^{2}$ , where center of circle is $(h, k)$ and $r$ is radius of circle.

Since, radius is measure of length from center to a point on circumference, so radius can't be negative.

Therefore, $r > 0 \Rightarrow r^{2} > 0$

It is given that center and radius of circle is determined by equation ${(x + 1)}^{2} + {(y - 5)}^{2} = - 4$ .

On comparing with standard equation of circle, we get $r^{2} = - 4$ which is not possible.

Therefore, we need to re-simplify the equation of circle and convert them in standar form of circle to find it's center and raidus.

Step by step

Solved in 2 steps

Knowledge Booster

$Equations$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, calculus and related others by exploring similar questions and additional content below.

Similar questions