I1the population toA.Evaluatey= 2e )2. When will the population reach 3 million?B. Solve 2e.026.3. How large will the population be in 3 yr?C.Evaluate y= 2e023)4. How large will the population be in 4 months?D.Solve 2e.02 3CONCEPT PREVIEW Radioactive Decay Strontium-90 decays according to the expo-nential functionyyoe 0.0241where t is time in years. Match each question in Column I with the correct procedure inColumn Il to answer thequestion.III5. If the initial amount of Strontium-90 is 200 g,A.Solve 0.75yo yoe0.0241thow much will remain after 10 yr?6. If the initial amount of Strontium-90 is 200 g,how much will remain after 20 yr?B.Evaluate y = 200e .0241 (10)7. What is the half-life of Strontium-90?C. Solve yo yoe 0.0241r.8. How long will it take for any amount ofStrontium-90 to decay to 75% of its initialD.Evaluate y = 200e 0.0241 (20)amount?(Modeling)exponential or logarithmic models. See Examples 1-6.The exercises in this set are grouped according to discipline. They involvePhysical Sciences (Exercises 9-28)An initial amount of a radioactive substance yo is given, along with information aboutthe amount remaining after a given time t in appropriate units. For an equation of theform y = yo ekt that mode ls the situation, give the exact value of k in terms of naturallogarithms.After 6 hr, 10 g remain.10. Уo -30gs9. yo= 60 g; After 3 hr, 20 g remain.12. yo = 20 mg; The half-life is 200 days.11. yo = 10 mg; The half-life is 100 days.14. yo= 8.1 kg; After 4 yr, O.9 kg remains.2.4 lb; After 2 yr, 0.6 lb remains.13. yo15. Decay of Lead A sample of 500 g of radioactive lead-210 decays to polonium-210according to the functionSolve each problem.A(t) = 500e 0.032;where t is time in years. Find the amount of radioactive lead remaining after(c) 20 yr.(d) Find the half-life.(b) 8 yr,(а) 4 yr,ల

Question
Asked Nov 24, 2019

15.

How do you answer part (a) and (d)?

I1
the population to
A.Evaluatey= 2e )
2. When will the population reach 3 million?
B. Solve 2e.02
6.
3. How large will the population be in 3 yr?
C.Evaluate y= 2e023)
4. How large will the population be in 4 months?
D.Solve 2e.02 3
CONCEPT PREVIEW Radioactive Decay Strontium-90 decays according to the expo-
nential function
yyoe 0.0241
where t is time in years. Match each question in Column I with the correct procedure in
Column Il to answer the
question.
I
II
5. If the initial amount of Strontium-90 is 200 g,
A.Solve 0.75yo yoe
0.0241t
how much will remain after 10 yr?
6. If the initial amount of Strontium-90 is 200 g,
how much will remain after 20 yr?
B.Evaluate y = 200e .0241 (10)
7. What is the half-life of Strontium-90?
C. Solve yo yoe 0.0241r.
8. How long will it take for any amount of
Strontium-90 to decay to 75% of its initial
D.Evaluate y = 200e 0.0241 (20)
amount?
(Modeling)
exponential or logarithmic models. See Examples 1-6.
The exercises in this set are grouped according to discipline. They involve
Physical Sciences (Exercises 9-28)
An initial amount of a radioactive substance yo is given, along with information about
the amount remaining after a given time t in appropriate units. For an equation of the
form y = yo ekt that mode ls the situation, give the exact value of k in terms of natural
logarithms.
After 6 hr, 10 g remain.
10. Уo -
30
gs
9. yo= 60 g; After 3 hr, 20 g remain.
12. yo = 20 mg; The half-life is 200 days.
11. yo = 10 mg; The half-life is 100 days.
14. yo= 8.1 kg; After 4 yr, O.9 kg remains.
2.4 lb; After 2 yr, 0.6 lb remains.
13. yo
15. Decay of Lead A sample of 500 g of radioactive lead-210 decays to polonium-210
according to the function
Solve each problem.
A(t) = 500e 0.032;
where t is time in years. Find the amount of radioactive lead remaining after
(c) 20 yr.
(d) Find the half-life.
(b) 8 yr,
(а) 4 yr,
ల
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I1 the population to A.Evaluatey= 2e ) 2. When will the population reach 3 million? B. Solve 2e.02 6. 3. How large will the population be in 3 yr? C.Evaluate y= 2e023) 4. How large will the population be in 4 months? D.Solve 2e.02 3 CONCEPT PREVIEW Radioactive Decay Strontium-90 decays according to the expo- nential function yyoe 0.0241 where t is time in years. Match each question in Column I with the correct procedure in Column Il to answer the question. I II 5. If the initial amount of Strontium-90 is 200 g, A.Solve 0.75yo yoe 0.0241t how much will remain after 10 yr? 6. If the initial amount of Strontium-90 is 200 g, how much will remain after 20 yr? B.Evaluate y = 200e .0241 (10) 7. What is the half-life of Strontium-90? C. Solve yo yoe 0.0241r. 8. How long will it take for any amount of Strontium-90 to decay to 75% of its initial D.Evaluate y = 200e 0.0241 (20) amount? (Modeling) exponential or logarithmic models. See Examples 1-6. The exercises in this set are grouped according to discipline. They involve Physical Sciences (Exercises 9-28) An initial amount of a radioactive substance yo is given, along with information about the amount remaining after a given time t in appropriate units. For an equation of the form y = yo ekt that mode ls the situation, give the exact value of k in terms of natural logarithms. After 6 hr, 10 g remain. 10. Уo - 30 gs 9. yo= 60 g; After 3 hr, 20 g remain. 12. yo = 20 mg; The half-life is 200 days. 11. yo = 10 mg; The half-life is 100 days. 14. yo= 8.1 kg; After 4 yr, O.9 kg remains. 2.4 lb; After 2 yr, 0.6 lb remains. 13. yo 15. Decay of Lead A sample of 500 g of radioactive lead-210 decays to polonium-210 according to the function Solve each problem. A(t) = 500e 0.032; where t is time in years. Find the amount of radioactive lead remaining after (c) 20 yr. (d) Find the half-life. (b) 8 yr, (а) 4 yr, ల

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Expert Answer

Step 1

Given that

A sample of 500 g of radioactive lead-210 decay to polonium-210 according the function as

A(t) 500e.032
Where t is time in years
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A(t) 500e.032 Where t is time in years

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Step 2

To find amount of lead remaining after

a)  4 years

Step 3

Plugging the value t = 4 in in the equation (1)

Then

amount of lea...

A(4) = 500e.03 D:4
A(4) 500e.128
1
A(4)(500) x
O.128
1
A(4) (500) x
{. 012=2.718123 =1.1365
1.1365
A(4)(500) x (0.87989)
A(4) 439.945 440g
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A(4) = 500e.03 D:4 A(4) 500e.128 1 A(4)(500) x O.128 1 A(4) (500) x {. 012=2.718123 =1.1365 1.1365 A(4)(500) x (0.87989) A(4) 439.945 440g

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