IBr decomposes according to the reaction at 150°C:2 IBr(g)= I2(g) + Br2(g) If IBr is placed in the container at an initial pressure of 5.0 atm, what will be its equilibrium pressure at 150°C? Kp= 8.3x10^-3
IBr decomposes according to the reaction at 150°C:2 IBr(g)= I2(g) + Br2(g) If IBr is placed in the container at an initial pressure of 5.0 atm, what will be its equilibrium pressure at 150°C? Kp= 8.3x10^-3
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter13: Fundamental Equilibrium Concepts
Section: Chapter Questions
Problem 92E: Antimony pentachloride decomposes according to this equation: SbCl5(g)SbCl3+Cl2(g) An equilibrium...
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IBr decomposes according to the reaction at 150°C:
2 IBr(g)= I2(g) + Br2(g)
If IBr is placed in the container at an initial pressure of 5.0 atm, what will be its equilibrium pressure at 150°C? Kp= 8.3x10^-3
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