Question
Asked Oct 25, 2019
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identify the absolute maximum and minimum values of the function on the given interval (when they exist). 

f(x)=x2/3(x-2) on [-2,2]

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Expert Answer

Step 1

Firstly, we find derivative of given function

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Step 2

Now, we find critical points of f(x) by solvingf'(x)=0

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5x-4 = 0 f(x) 0 3x3 4 x 5

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Step 3

Now, we find value of function at end-point...

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2 f(x)x (x-2) f(-2)=(-2)3 (-2-2)- -6.35 -Bte 4 =-1.03 f(2)(2)5 (2-2)- 0

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Tagged in

Math

Calculus

Derivative