Question
Asked Oct 9, 2019
If 3.01 mol of an ideal gas has a pressure of 8.45 atm and a volume of 76.23 L, what is the temperature of the sample?
Т-
К
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If 3.01 mol of an ideal gas has a pressure of 8.45 atm and a volume of 76.23 L, what is the temperature of the sample? Т- К

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Step 1

The effect of temperature and pressure on the volume of a gas is given by the equation called the ideal gas equation. It is expressed as follows:

PV= nRT                 …… (1)

Here, P is the pressure,  is the volume, n is the number of moles, R is the gas constant and T is the temperature.

Step 2

Substitute 3.01 mol for n, 8.45 atm for p, 76.23 L for V and 0.0821 atm...

3.01 molx 0.0821 atmLmol K'xT
8.45 atmx 76.23L
0.2471 atmLKxT
644.14 atmL
644.14 atmL
T
0.2471 atmLK
= 2606.8 K
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3.01 molx 0.0821 atmLmol K'xT 8.45 atmx 76.23L 0.2471 atmLKxT 644.14 atmL 644.14 atmL T 0.2471 atmLK = 2606.8 K

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