Question
Asked Nov 30, 2019
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If a 275ml flask were used to collect oxygen gas what size sample of KCl03 could be used to generate oxygen at stp without exceeding the volume of the flask? 

2KClO3 → 2KCl +3O2

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Expert Answer

Step 1

Given:

Volume of O2 = 275 mL = 0.275 L.

Chemical reaction:

2KClO3 → 2KCl +3O2

Step 2

Calculation for number of moles:

At STP, 1 mole of any gas occupies 22.4 Litre of Volume

1 mole 22.4 L
х mole ->
0.275 L
0.275 L x 1 mole
х 3D
22.4 L
х3D 0.0123 moles
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1 mole 22.4 L х mole -> 0.275 L 0.275 L x 1 mole х 3D 22.4 L х3D 0.0123 moles

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Step 3

Calculation for moles of ...

2 moles of KCI03 -3 moles of 02
0.0123 moles of 02
x moles of KCIO3
0.0123 moles of O2 x 2 moles of KC1O3
х‑
3 moles of 02
0.0082 moles of KC1O3
x
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2 moles of KCI03 -3 moles of 02 0.0123 moles of 02 x moles of KCIO3 0.0123 moles of O2 x 2 moles of KC1O3 х‑ 3 moles of 02 0.0082 moles of KC1O3 x

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