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If a ball is thrown into the air with a velocity of 42 ft/s, its height (in feet) after t seconds is given by y = 42t - 16t2. Find the velocity when t 1

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please help with question (answer is not 26 ive already tried it)

If a ball is thrown into the air with a velocity of 42 ft/s, its height (in feet) after t seconds is given by y = 42t - 16t2. Find the velocity when t 1
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If a ball is thrown into the air with a velocity of 42 ft/s, its height (in feet) after t seconds is given by y = 42t - 16t2. Find the velocity when t 1

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Step 1

Given,

...
Height, y 42t - 16t2 where t is the time in seconds
dy
. Velocity
dt
d(42t-16t2)
dt
= 42 - 32t
. Velocity when t is 1 = 42 - 32 x 1
= 42 - 32
10 ft/s
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Height, y 42t - 16t2 where t is the time in seconds dy . Velocity dt d(42t-16t2) dt = 42 - 32t . Velocity when t is 1 = 42 - 32 x 1 = 42 - 32 10 ft/s

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Calculus

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