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Asked Sep 14, 2019
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If a ball is thrown into the air with a velocity of 42 ft/s, its height (in feet) after t seconds is given by y = 42t - 16t2. Find the velocity when t 1
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If a ball is thrown into the air with a velocity of 42 ft/s, its height (in feet) after t seconds is given by y = 42t - 16t2. Find the velocity when t 1

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Expert Answer

Step 1

Given that, the velocity of a ball which is thrown into air is 42 ft per s. The expression of it’s height (in feet) after t seconds is given as,

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y 42-16

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Step 2

The height of the ball when t i...

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y 42(1)-16(12 26 ft

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Math

Calculus

Differential Equations

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