If ln3=a and ln2=b then what is the solution of the following equation in terms of a and b? 10/1+4e^(-.01x) = 2.5   -100(a/b) 100(2b-a) 100(a-b/2) -100(a/b^2)

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Chapter6: Exponential And Logarithmic Functions
Section6.7: Exponential And Logarithmic Models
Problem 15TI: Cesium-137 has a half-life of about 30 years. If we begin with 200 mg of cesium-137, will it take...
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If ln3=a and ln2=b then what is the solution of the following equation in terms of a and b?

10/1+4e^(-.01x) = 2.5

 

-100(a/b)

100(2b-a)

100(a-b/2)

-100(a/b^2)

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