If R1 = 0xEF00DE12, R2 = 0x0456123F, R5 = 4, R6 = 28; Find the values of the destination registers for the following instruction? a) LSL R1, #8 b) ASR R1, R5 c) ROR R2, R6 d) LSR R2, #6 Substantiate your answers appropriately.
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- Assume the following register contents: $t0 = 0x01234567, $t1 = 0x56781234. Set back to these values back after answering each question. For the register values shown above, what is the value of $t2 for the following sequence of instructions? sll $t2, $t0, 31 andi $t3, $t2, 10STATEMENT- THE FOLLOWING DATA IS STORED IN THEMEMORY LOCATIONSSTARTING FROM 3060H USING MEMORY RELATED INSTRUCTIONS(NOT MANUALLY). WRITE PROGRAM TO COUNT THE NUMBERSONLY IF D6 AND D0 BITS ARE 1, ELSE REJECT THE NUMBER. STORETHE COUNTED NUMBERS STARTING FROM MEMORY LOCATION3070H AND STORE THE COUNT IN ‘D’ REGISTER.DATA (H): 80, 71, 52, E7, 78, F2, 67, 35, 62, 08, 17. Write program in assembly language on sim8085Assume the following register contents: $t0 = 0x01234567, $t1 = 0x56781234. Set back to these values back after answering each question. For the register values shown above, what is the value of registers ($t0, $t1, $t2, $t3) after executing each instruction? sll $t2, $t0, 2 and $t3, $t2, $t1
- Use the register and memory values in the table below for this question. Assume a 32-bitmachine. Assume each of the following questions starts from the table values; that is, DO NOT use valuechanges from one question as propagating into future parts of the question.Register Value Memory LocationValueR1 12 12 16R2 16 16 20R3 20 20 24R4 24 24 28a) Give the values of R1, R2, and R3 after this instruction: add R1, R2, R3b) What values will be in R1 and R3 after this instruction is executed: lw R2, 8(R1)c) What values will be in R2 and R4 after this instruction is executed: addi R2, R4, #16NOTE: This is an assembly class, so these programs must be coded in Pi 5 - In a normal swap a temporary variable is needed, eg "r2 = r0; r0 = r1; r1 = r2; " swaps r0 and r1. A swap can be implemented without the temporary r2 register using xor operations (the eor instruction). Write a program to swap two registers using eor instructions. # Program File: Neg.s# Purpose: This program reads a number and prints out the negative value. .text.global mainmain: #Push stack SUB sp, sp, #4 STR lr, [sp, #0] #Prompt and read number LDR r0, =prompt BL printf LDR r0, =format LDR r1, =number BL scanf #Calc negative LDR r1, =number LDR r1, [r1] MVN r1, r1 ADD r1, r1, #1 #Print Answer LDR r0, =output BL printf #Pop stack MOV r0, #0 // Make the program return true LDR lr, [sp, #0] ADD sp, sp, #4 MOV pc, lr.data prompt: .asciz "\nEnter a number: " output: .asciz "\nThe negative value is %d\n" number: .word 0 format: .asciz "%d"Question1: Multiple Choice: (please leave it to other tutors who can answer all my sub-question since this is my last question for this month) 2-The elements of the ISA for a particular type of CPU include a. addressing modes b. data types c. instructions d. a and b e. a, b and c Question 2: Perform the following logical operations and express your answers in hexadecimal notation. x3487 AND x7254 xABCD or x3234 xF098 XOR x3344
- Convert given code to LEGv8 code:int f, g, y //global 64-bit variablesint sum (int a, int b) { // at memory address X0+1000.return (a +b)} int main (void) // at memory address X0 + 800{f=2;g=3;y= sum (f, g);return y;}Convert this code, making valid assumptions about registers and register use. Notethat brackets and global variable declarations are not affecting the addresses of the instructionsin memory.Assume the two instructions below are executed.AND R4, R4, #0STR R4, R7, #-1Which one of the statements below is correct? Group of answer choices The execution sets the value at memory address with label H to x1233. The execution sets the value in R4 to x400F. The execution sets the value at memory address with label H to x1234. The execution sets the value at memory address with label H to 0. The execution sets the value at memory address with label B to x1233.Which statement is correct for the memory segments in 8086 microprocessor? a. For Stack segment, the offset address can be a direct value. b. The offset address for program instructions is taken from SP register. c. Variables created in the Assembly program are stored in Data segment. d. Segment address for executing sub-routines is taken from ES register.
- f R0 = 0x20008000, after executing STMIA r0!, {r3, r9, r7, r1, r2}, register r7 will be stored in memory starting from which bases. Please choose one:A. R0 = 0x2000800CB. R0=0x20008004C. R0= 0x20008014D. R0 = 0x20008010E. R0 = 0x20008008Assume the following register contents:$t0 = 0xAAAAAAAA, $t1 = 0x12345678a) For the register values shown above, what is the value of $t2 for the following sequenceof instructions? sll $t2, $t0, 6or $t2, $t2, $t1b) For the register values shown above, what is the value of $t2 for the following sequenceof instructions? sll $t2, $t0, 8andi $t2, $t2, -1c) For the register values shown above, what is the value of $t2 for the following sequenceof instructions? srl $t2, $t0, 3andi $t2, $t2, 0xFEFEOBJECTIVETo perform the basic arithmetic and logical operations using the 8086 Microprocessor emulator. Take a screenshot of your code and output. Create the code and run the following operations: 4. LOGICAL OR OPERATIONALGORITHMStep 1. Allocate some space for the result in data segmentstep 2. In code segment, store accumulator with some valuestep 3. Store B register with some valuestep 4. Perform OR operation on register content with accumulatorstep 5. Result is stored in accumulatorstep 6. The result is stored in required memory location. SAMPLE INPUTS & OUTPUTSBefore Execution: After Execution:AX = 0001H AX = 0001HBX = 0000H