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If the specific heat of a solution is 4.18 J/goC, and you have 161 mL (1.03 g/mL) which increases in temperature by 3.6 degrees, how many kilojoules did the solution absorb?

Question

If the specific heat of a solution is 4.18 J/goC, and you have 161 mL (1.03 g/mL) which increases in temperature by 3.6 degrees, how many kilojoules did the solution absorb?

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Step 1

Mass of solution in grams is ...

Mass Densityx Volume
(1.03 g/mL) (161 mL)
165.83 g
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Mass Densityx Volume (1.03 g/mL) (161 mL) 165.83 g

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