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CalculusQ&A LibraryIf we neglect air resistance, then the range of a ball (or any projectile) shot at an angle θ with respect to the x axis and with an initial velocity v0, is given byR(θ)=v02g sin(2θ) for 0 ≤ θ ≤ π2 where g is the acceleration due to gravity (9.8 meters per second per second).For what value of θ is the maximum range attained? (Note that the answer is numerical, not symbolic.)θ =Question

Asked Oct 7, 2019

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If we neglect air resistance, then the range of a ball (or any projectile) shot at an angle θ with respect to the x axis and with an initial velocity v_{0}, is given by

R(θ)=

v_{0}^{2} |

g |

sin(2θ) for 0 ≤ θ ≤

π |

2 |

where g is the acceleration due to gravity (9.8 meters per second per second).

For what value of θ is the maximum range attained? (Note that the answer is numerical, not symbolic.)

θ =

Step 1

Given,

Step 2

On differentiating, we get

Step 3

Now computing the point where first...

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