Question
Asked Oct 7, 2019
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If we neglect air resistance, then the range of a ball (or any projectile) shot at an angle θ with respect to the x axis and with an initial velocity v0, is given by

R(θ)=

v02
g

 sin(2θ)      for 0 ≤ θ ≤ 

π
2

 

where g is the acceleration due to gravity (9.8 meters per second per second).

For what value of θ is the maximum range attained? (Note that the answer is numerical, not symbolic.)

θ = 

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Expert Answer

Step 1

Given,

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Step 2

On differentiating, we get

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Step 3

Now computing the point where first...

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Image Transcriptionclose

R'(0) 0 2 |cos (20) 0 go cos (20) 0 20 2 cos 0 = 2 4

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Tagged in

Math

Calculus

Derivative

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