If we stand on top of a 130-foot building and throw a ball up into the air with an initial velocity of 25 feet per second, then the height of the ball above the ground is given by the following.H = −16t2 + 25t + 130Here t is time in seconds, and H is measured in feet.(a) Complete the following table giving the value H at time t.tH0      0.25 0.5   0.75 1      1.25 1.5   1.75 2      2.25 2.5   2.75 3      3.25 3.5   3.75 4      (c) Find the value of t that maximizes H. (Round your answer to two decimal places.)t =  sec(d) Find the maximum value of H. (Round your answer to two decimal places.)H =  ft

Question
Asked Dec 12, 2019
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If we stand on top of a 130-foot building and throw a ball up into the air with an initial velocity of 25 feet per second, then the height of the ball above the ground is given by the following.
H = −16t2 + 25t + 130
Here t is time in seconds, and H is measured in feet.
(a) Complete the following table giving the value H at time t.
t H
0       
0.25  
0.5    
0.75  
1       
1.25  
1.5    
1.75  
2       
2.25  
2.5    
2.75  
3       
3.25  
3.5    
3.75  
4       


(c) Find the value of t that maximizes H. (Round your answer to two decimal places.)
t =  sec

(d) Find the maximum value of H. (Round your answer to two decimal places.)
H =  ft

  

 

 
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Expert Answer

Step 1

Part a) Complete the given table

Part b) Determine the value of t for which the height is maximum.

Part c) Determine the maximum height.

Step 2

Given:

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h(t) = -16h + 25t +130 h(i) 0.25 0.5 0.75 1.25 1.5 1.75 2.25 2.5 2.75 3.25 3.5 3.75 4.

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Step 3

Compute the value of the function h(t) for different va...

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h(t) 130 0.25 135.25 0.5 138.5 0.75 139.75 139 1.25 130.25 1.5 131.5 1.75 124.75 110 105.25 2.25 2.5 92.5 2.75 77.75 61 3.25 42.25 3.5 21.5 3.75 -1.25 -20

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Math

Algebra