IL V) = 230 sin(314t - 30°) L = 2.2H

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A: Asper guidelines i have to do only one . please post remaining again. Given that

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A:

Q: 2. Relation between currents according to KCL is 12 i1 i5

A: .

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A: The solution can be achieved as follows.

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A:

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A: The amount of power dissipated through a resistor can be expressed in the following way:

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A: The circuit can be made as:

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A: The solution can be achieved as follows.

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Q: A charge of 15C flow in a conductor in .5 *:2min, then the current produced is 125A O 0.125A O 12.5A…

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Current Division Method

The generalized current divider formula is given by the following relation below,