Imagine that in red blood cells (RBCS) the following concentrations were noted for the "adenylate pool": [ATP] = 2000 uM; [ADP] = 270 uM; and [AMP] = 30 uM. Assume that the pH is 7 and remains constant. a) calculate the Energy change (EC) (to four decimal places for RBCS given the above values. Show work b) If the [ATP] decreases by 5%, calculate the new [ATP], [ADP], and [AMP] given that the concentrations of all three species are "connected" by the adenylate kinase reaction, which is shown below. You will need to use the quadratic equation for this one. show your work.

Biochemistry
6th Edition
ISBN:9781305577206
Author:Reginald H. Garrett, Charles M. Grisham
Publisher:Reginald H. Garrett, Charles M. Grisham
Chapter18: Glycolysis
Section: Chapter Questions
Problem 16P: Energetics of the Hexokinase Reaction The standard-state free energy change. Gfor the hexokinase...
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Imagine that in red blood cells (RBCS) the
following concentrations were noted for the
"adenylate pool": [ATP] = 2000 uM; [ADP] = 270
uM; and [AMP] = 30 uM. ASsume that the pH is
7 and remains constant.
a) calculate the Energy change (EC) (to four
decimal places for RBCS given the above values.
Show work
b) If the [ATP] decreases by 5%, calculate the
new [ATP], [ADP], and [AMP] given that the
concentrations of all three species are
"connected" by the adenylate kinase reaction,
which is shown below. You will need to use the
quadratic equation for this one. show your work.
%3|
%3D
ADP + ADP
ATP + AMP Keq = 0.44
Transcribed Image Text:Imagine that in red blood cells (RBCS) the following concentrations were noted for the "adenylate pool": [ATP] = 2000 uM; [ADP] = 270 uM; and [AMP] = 30 uM. ASsume that the pH is 7 and remains constant. a) calculate the Energy change (EC) (to four decimal places for RBCS given the above values. Show work b) If the [ATP] decreases by 5%, calculate the new [ATP], [ADP], and [AMP] given that the concentrations of all three species are "connected" by the adenylate kinase reaction, which is shown below. You will need to use the quadratic equation for this one. show your work. %3| %3D ADP + ADP ATP + AMP Keq = 0.44
Expert Solution
Step 1

The energy change or Gibb's energy change is difference in energy of products and reactants (G) in a reaction.

Step 2

(a) In R.B.C, concentration of adenylate pool is given as [ATP]= 2000μM, [ADP]=270 μM, and [AMP]= 30μM.

Formula for free energy change is given as:

G=G°+RT lnQwhere;G= energy change for reaction at given concentrations of reactants and productsG°=standard energy change for reaction at equilibrium concentrationQ= Reaction quoteint=[Products}[Reactants]R=gas constant=8.314 J/K.moleT=37°C=310 K

Now at equilibrium G=0, so:

G°=-RTlnKeqwhere Keq= equilibrium constant=0.44 (given)G°=-8.314×310×ln(0.44)G°=-2115.9460 J/mol

So G=-2115.9460+8.314×310×ln2000×30270×270=-2115.9460-502.0634=-2618.0094J/mol

 

or G=-2.6180 KJ/mol

Hence, energy change for R.B.C for given adenylate pool is -2.6180 KJ/mol or for converting from ADP to ATP and AMP, there is release of 2.6180 KJ/mol of energy and reaction is spontaneous.

 

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