# Imagine two solutions with the same concentration and theNormal boiling pointsame boiling point, but one has benzene as the solvent andSolventк, (С/m)(°C)the other has carbon tetrachloride as the solvent. Determinebenzene80.12.53the molal concentration, m (or b), and boiling point, T,.carbon tetrachloride76.85.03тТь -||

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Step 1

Colligative properties are the properties which depend on the number of atoms or molecules or ions or particles present in the solution. Some common colligative properties are depression in freezing point, elevation in boiling point, osmotic pressure and relative lowering in vapor pressure.

Elevation in boiling point is a colligative property that can be calculated with the help of concentration of solution. The relation between Elevation in boiling point and concentration of solution can be written as:

Elevation in boiling point = ∆Tb = Tsolute + Tsolvent =  kb x molality

Step 2

Assume two solutions A and B:

Solution A with benzene:

Boiling point of benzene = 80.1 ◦C

Kb for benzene solvent = 2.53 ◦C x kg / moles

Boiling point of A = TA

For the solution of A:

Step 3

For the solution of B:

Since the molality of both solutions is same, hence compare equation (1) and (2) :

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