In a double slit experiment, the distance between the slits is 0.2 mm and the distance to the screen is 150 cm. What is the phase difference (in degrees) between the waves from the two slits arriving at a point P when the angular distance of P is 10° relative to the central peak, and the wavelength is 500 nm? (Convert your result so the angle is between 0 and 360°.) a. 145° b. 155° 165° c. d. 135° 95° e. ANS: C PTS: 3 DIF: Challenging

A person is standing a distance d = 1.35 m away from a mirror, which is m = 0.870 m above the ground, as shown in Figure 1. Light hits their foot, reflects off of the mirror, and enters their eye (this is how they see the reflection of their foot!). How tall are they? (Measure their height h from the ground to their eye, and don't worry about the small distance from their eye to the top of their head, which we do not have enough information to determine).

One positive lens (focal length = f1) and one negative lens (focal length = -f2) are placed at a distance d. – All lenses are thin lenses. Find the overall ABCD matrix of the system Find the value of d when “C” of the overall matrix is zero. ( Hint : Find d in terms of f1 and f2) (This is when the focal length of the overall system is infinity.)

The vertical distance between eye level and the ground for a certain swimmer, who is standing upright, is 1.55 m. If the swimmer is standing 2.00 m from the edge of a 2.50-m-deep swimming pool, how far from the base of the pool will the swimmer be able to see a coin that is at the bottom of the pool? The swimmer is represented by the upward directed arrow in the diagram, and the distance between the base of the pool and the coin is “d”. The index of refraction of water is 1.33.   a. 1.55 m   b. 0.950 m   c. 1.85 m   d. 2.15 m   e. 1.25 m