In a local bar, a customer slides an empty beer mug down the counter for a refill. The height of the counter is 1.16 m. The mug slides off the counter and strikes the floor 1.80 m from the base of the counter.(a) With what velocity did the mug leave the counter?(b) What was the direction of the mug's velocity just before it hit the floor?

Question
Asked Nov 12, 2019
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In a local bar, a customer slides an empty beer mug down the counter for a refill. The height of the counter is 1.16 m. The mug slides off the counter and strikes the floor 1.80 m from the base of the counter.

(a) With what velocity did the mug leave the counter?
(b) What was the direction of the mug's velocity just before it hit the floor?
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Expert Answer

Step 1

Let the height of the counter be y and x is the width of the wedge-shaped counter.

y =1.16 m
x 1.80 m
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y =1.16 m x 1.80 m

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Step 2

By considering the initial velocity of the mug to be zero (that is, vyi=0 m/s), write motion’s equation and plug the required values to find the time(t) taken by mug to slides down.

1
y vtg
yi
y =(0 m/s)fg
2
2y
g
2(1.16 m)
V (9.8 m/s)
t0.487 s
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1 y vtg yi y =(0 m/s)fg 2 2y g 2(1.16 m) V (9.8 m/s) t0.487 s

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Step 3

(a) Write the speed-distance formula and plug the required values to find the x- component of ...

t
(1.8 m)
(0.487 s
= 3.7 m/s
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t (1.8 m) (0.487 s = 3.7 m/s

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