In a mixture of two gases, the partial pressure of methane is 0.175atm and the partial pressure of oxygen is 0.250atm.
If the gases occupy a volume of 10.5 liters at 65 degrees Celsius, what is the number of moles of methane in the mixture?
Given,
Partial pressure of methane = 0.175 atm
Partial pressure of oxygen = 0.250 atm
Volume, V = 10.5 L
Temperature, T = 65 oC = (65 + 273) K = 338 K
Total pressure, P = 0.175 atm + 0.250 atm = 0.425 atm
The total number of moles (n) can be calculated using the ideal gas equation as:
PV nRT PV n = RT 0.425 atm X 10.5 L n = Latm 0.0821 x 338 K mol K n 0.161 mol
Mole fraction of methane ca...
Partial pressure of methane Mole fraction of methane x total pressure Partial pressure of methane Mole fraction of methane Total pressure 0.175 atm Mole fraction of methane =0.412 0.425 atm
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