In a particular experiment, it was found that the concentration of N O; in liquid bre Tir with time as follows: 2 N₂O5(g) 4 NO2(g) + O2(g) Time (s) [N₂O5] a. 2.2073 b. 0.0623 Calculate the value of the rate constant (k) C. 0.0962 d. 9E-05 e. 1.8502 |0.110 f. 0.0021 200 400 600 0.110 0.073 1000 0.048 0.032 0.014

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Chapter13: Rates Of Reaction
Section: Chapter Questions
Problem 13.51QP: In experiments on the decomposition of azomethane. CH3NHCH3(g)C2H6(g)+N2(g) the following data were...
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Tir
In a particular experiment, it was found that the concentration of N₂O5 in liquid bre
with time as follows:
2 N₂O5(g)
4 NO2(g) + O2(g)
1
[N₂05] 0.110
Time (s)
a 2.2073
Calculate the value of the rate constant (k)
b. 0.0623
C.
0.0962
d 9E-05
e. 1.8502
f. 0.0021
For the reaction,
2N₂O5(g)
Time
0
100
300
600
900
The following data were obtained:
T = 339 K
[N₂O), M
a. 45.8 kJ/mol
0
b. 120.6 kJ/mol
C.
112.5 kJ/mol
d. 95.7 kJ/mol
e. 68.5 kJ/mol
200 400 600
1000
0.073 0.048 0.032 0.014
f.
89.7 kJ/mol
4NO2(g)
1.00 × 10
6.14 10
2.33 107
5.41- 10¹
1.26 × 10
+
Find the Ea using the best-fit straight line of the three rate constants at the three temperature
values.
O2(g)
T = 310 K
[N₂O.]. M
1.00 × 10
9.54 × 10
8.63
10²
7.43 10
6.39 × 10
T = 304 K
[N₂O₁]. M
1.00 × 10
9.69 × 10
9.15 10
8.40 - 10
7,70 10-
Transcribed Image Text:Tir In a particular experiment, it was found that the concentration of N₂O5 in liquid bre with time as follows: 2 N₂O5(g) 4 NO2(g) + O2(g) 1 [N₂05] 0.110 Time (s) a 2.2073 Calculate the value of the rate constant (k) b. 0.0623 C. 0.0962 d 9E-05 e. 1.8502 f. 0.0021 For the reaction, 2N₂O5(g) Time 0 100 300 600 900 The following data were obtained: T = 339 K [N₂O), M a. 45.8 kJ/mol 0 b. 120.6 kJ/mol C. 112.5 kJ/mol d. 95.7 kJ/mol e. 68.5 kJ/mol 200 400 600 1000 0.073 0.048 0.032 0.014 f. 89.7 kJ/mol 4NO2(g) 1.00 × 10 6.14 10 2.33 107 5.41- 10¹ 1.26 × 10 + Find the Ea using the best-fit straight line of the three rate constants at the three temperature values. O2(g) T = 310 K [N₂O.]. M 1.00 × 10 9.54 × 10 8.63 10² 7.43 10 6.39 × 10 T = 304 K [N₂O₁]. M 1.00 × 10 9.69 × 10 9.15 10 8.40 - 10 7,70 10-
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