Question

Asked Jul 5, 2019

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In a population of ages where the mean age is 45 and the standard deviation is 5.25, what are the ages of the youngest 5% and the oldest 5%. Round your solutions to the nearest tenth.

Step 1

Given mean age = 45

Standard deviation = 5.25

The Z score with 0.0505 to its left is -1.64 and the Z score with 0.0495 to its left is -1.65. So we can say on average the Z score with 0.05 to its left is -1.645.

Step 2

Using the formula of Z score and by substituting the values we get the age of youngest 5% is 36.4 (rounded to tenth place).

Step 3

The Z score with 0.0505 to its right is 1.64 and the Z score with 0.0495 to its right is...

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