In a simple random sample of 144 households in a county in Virginia, the average number of children in these households was 3.62 children. The standard deviation from this sample was 2.40 children. A 90% confidence interval for the mean number of children in all households in this county is?

Q: The average salary of 64 employee was 5400 and the sample standard deviation was 280. Find the 90%…

A:

Q: From a random sample of 64 high school seniors, the sample mean and standard deviation of the math…

A: The sample size is 64, sample mean is 96, and standard deviation is 16. The degrees of freedom is,…

Q: The operator of a nuclear power plant requires fuel rods to have a mean percentage of enrichment of…

A:

Q: From a simple random sample of 400 of the 1,395 colleges in our population, it was found that…

A: Given : 1395 colleges in our population  Population Size (N) = 1395 400 colleges selected randomly…

Q: We take a sample of 50 people and obtain a sample mean of 147 pounds with a standard deviation of 15…

A: We have given that  Sample size n = 50 Sample mean = 147 Standard deviation = 15 90%confidence…

Q: A Gallup poll of 1001 Americans age 18 and over conducted in May of 2013 found that 80% of the…

A: Confidence Interval: Confidence interval is the interval estimate of the population parameter. It is…

Q: A sample of 47 Charleston County households have a mean income of $32,346 with a standard deviation…

A: The sample size is 47, sample mean is $32346, and sample standard deviation is $8571. The confidence…

Q: For a single sample of n = 16 scores, the tabled t values used to determine the 99 percent…

A: Given: n = 16 Confidence Interval = 99% α=1-0.99=0.01α2=0.012=0.005 Degrees of freedom:…

Q: In an examination of purchasing patterns of shoppers, a sample of 16 shoppers revealed that they…

A: From the given information, sample mean, x̅=54 Population standard deviation, σ=21 Sample size n =16…

Q: A random sample of 51 four-year-olds attending day care centers provided a yearly tuition average of…

A:

Q: find the t/α2 value for an 85% confidence interval for the mean when the sample size is 12

A: We have to find correct answer..

Q: Given a sample of size n=20 and the sample mean of 10 and a standard deviation of 3, find the…

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Q: Find the 95% confidence interval for the mean score of all such subjects. Round to one decimal…

A: Given : n=27 , X-bar=76.2  , s=21.4  , α=0.05 Since , the population standard deviation (σ) is…

Q: The mean for the verbal component of the SAT is reported as 500, with a standard deviation of 100. A…

A: It is given that the sample mean is 498 and the population standard deviation is 100.

Q: A college admissions officer takes a simple random sample of 96 entering freshmen and computes their…

A: We have to find out lower confidence interval...

Q: How large a sample should be selected to provide a 95% confidence interval with a margin of error of…

A: Given : Margin of error = 5 α = 0.05 Population standard deviation = σ = 30 zα2 = z0.052 = 1.96

Q: Nine tests of a new jet engine yielded a mean thrust of 7600 pounds with a standard deviation of 90…

A: Given values, x¯=7600σ=90n=9z(95%)=1.96

Q: A sample of 14 commuters in Cebu showed the average of the commuting times was 33.2 minutes. If the…

A: GivenSample size (n) = 14SD(s) = 8.3 minutesaverage (x) = 33.2 minutes 95% confidence interval.…

Q: Find the 98% confidence interval for the difference between the means of the two populations

A: Given that sample size n = 18 Mean difference = 22.9 And SD sd = 2.2 The critical value of t at (n -…

Q: In the 2018 GSS, a random sample of 1419 adults were asked how many hours per week they usually…

A: Given Data : Sample Size, n = 1419.0 Sample Mean, x̄ = 7.15 standard…

Q: The average sa!lary of 64 employee was 5400 and the sample standard deviation was 260. Find the 95%…

A: Solution

Q: In the context of the previous question, construct a 95% confidence interval of the mean salary of…

A: Note- Here I giving a solution for the second photo.   Given information- Sample size, n = 40…

Q: Given a mean of 483, a standard deviation of 29, and a sample size of 60, construct a 95 %…

A: A mean of 483, a standard deviation of 29, and a sample size of 60, construct a 95% confidence…

Q: The average salary of 64 employee was 5400 and the sample standard deviation was 270. Find the 90%…

A:

Q: A survey of 31 accountants shows the average salary is $65,000 with a population std deviation of…

A: Given : Sample size, n= 31 Mean = $65000 Population standard deviation = 7000

Q: (a) What sample size is required to obtain a 95% confidence interval with an approximate margin of…

A: It is given that margin of error (E) is 0.027 and the confidence level is 0.95.

Q: A sample of part time students are asked how many hours per week they work on a job. For the…

A: Given: n=5

Q: The daily intakes of milk (in ounces) for ten randomly selected people were: 23.3 28.4 10.5 16.4…

A: Confidence interval: The (1-α) % confidence interval for population standard deviation is given by:

Q: Given a mean of 62, a standard deviation of 8, and a sample size of 150, construct a 99.7%…

A: Given that a mean of 62, a standard deviation of 8 and a sample size of 150. We have to construct a…

Q: An investigative reporter contacts a random sample of hotels, and finds a 95% confidence interval…

A: Given that  The 95% confidence interval for the proportion of hotels in the united states have…

Q: How large a sample should be used to provide a 95% confidence interval with a margin of error of 4,…

A:

Q: When computing a 95 percent confidence interval for a with a sample of 30, what values of g would we…

A: The chi-square statistic is used to determine the critical values for the confidence intervals for…

Q: For a given sample, a 50% confidence terval for the population mean is narrower than a 90%…

A: For  a given sample size and population standard deviation, the interval estimation of the…

Q: 530 males in the sample who gave a numeric response from 0 to 6, the mean was 2.51 and the standard…

A: Provided information is, n =530 x̅ =2.51 s =0.87 90% confidence interval can be calculated as:…

Q: A poll of 2500 people shows that 50% approve of a smoking ban in bars and restaurants in Kentucky.…

A: Given, n = 2500 p = 50% = 0.50 At 95% Confidence level, the value of Z is 1.96

Q: In a random sample of 100 basketball players,the average vertical jump was 38 inches. If you somehow…

A: a) The margin of error is, Thus, the margin of error is 1.96 inches.

Q: Calculate the 95% confidence interval and the 99% confidence interval for a sample of 81 where the…

A: Given : Sample Size, n = 81 Sample Mean, x̄ = 50 sample standard…

Q: The average salary of 64 employee was 5400 and the sample standard deviation was 260. Find the 90 %…

A:

Q: An economist is interested in studying the incomes of consumers in a particular country. The…

A: The population standard deviation = $1,000.Z value for 90% confidence interval is 1.645.Sample size…

Q: If X̅ = 65, ? = 20 ??? ? = 36, construct a 95% confidence interval estimate for the population mean,…

A:

Q: A random sample of 12 students showed the following time (in hours) of sleep 4.5 5 5.5 6 6 7 7.5 7.5…

A:

Q: In a random sample of 50 people, the mean body mass index (BMI) was 27.7 and the standard deviation…

A: Given that the sample size is 50, the mean is 27.7 and the standard deviation is 6.12 a) Confidence…

Q: he following stemplot shows the swimming speeds, in kilometers per hour  (km/h), for a random sample…

A: xbar = 9.771 s = 0.944 n = 31

Q: A random sample of 17 hotels in Boston had an average nightly room rate of $165.40 with a sample…

A: It is given that  Sample mean = $165.40 Sample standard deviation = $21.70 Sample size = 17

Q: In a study of government financial aid for college​ students, it becomes necessary to estimate the…

A: The required sample size is calculated by using the formula:

Q: What is the smallest sample size required to provide a 95% confidence interval for a mean, if it…

A: We want to find the sample size  Given Margin of error=E=1 Standard deviation=σ=3 The critical value…

Q: The average weight of 35 randomly compact automobiles was 2680. The sample standard deviation was…

A: From the provided information, Sample size (n) = 35 Sample mean (x̅) = 2680 Sample standard…

Q: In the construction of an 88% Confidence Interval for a population mean u, a has the value of

A: Incomplete