In a study of 200 accidents that required treatment in an emergency room, 80 occurred at work. Find the 90% confidence interval of the true proportion of accidents that occurred at work

Q: In a survey of 2279 ​adults, 729 say they believe in UFOs. Construct a 90% confidence…

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Q: A survey of 540 depressed shoppers found at 32% of them shop on impulse. What is the 99% confidence…

A: Given : Sample Size, n = 540 confidence level,c=0.99 Significance level, α…

Q: A survey of 200,000 boat owners found that 12% of the pleasure boats were named Serenity.Find the…

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Q: 5.From a sample of 1,000 college students, 28% watch the Super Bowl game each year. Find the margin…

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Q: When Mendel conducted his famous genetics experiments with peas, one sample of offspring consisted…

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Q: In a recent poll, 430 people were asked if they liked dogs, and 41% said they did. Find the margin…

A: It is given that the value of n is 430, p hat is 0.41 and the confidence level is 0.99.

Q: In a recent survey of 200 households, 172 had central air conditioning.  Find the 85% confidence…

A: Given that In a recent survey of 200 households, 172 had central air conditioning That is…

Q: Of 380 randomly selected medical students, 21 said that they planned to work in a rural community.…

A: Sample proportion=p^=21380z=critical value for 95% confidence interval=1.96n=sample size=380

Q: Find the margin of error for the given confidence level.

A: Margin of error :  In a confidence interval, the range of values above and below the sample…

Q: In a random sample of 500 people eating lunch at a cafeteria on various Fridays, it was found that…

A: Given that Sample size n= 500  Favorable cases x=160 Sample proportion p^=x/n

Q: A Gallup Youth Survey in 2001 found that of 501 randomly selected teenagers in the U.S., 271 of them…

A: Given Total number of teenagers selected = 501Number of teenagers said who get along with their…

Q: In a survey of 1037 US adults ages 65 and over, 643 were concerned about getting the flu. A 99%…

A: Given,n=1037x=643p^=xnp^=6431037=0.6201-p^=1-0.620=0.380α=1-0.99=0.01α2=0.005Z0.005=2.58    (from…

Q: In a recent poll, 560 people were asked if they liked dogs, and 22% said they did. Find the margin…

A: For 95% confidence intervalα=1-CI=1-0.95=0.05So, zα2=z0.052=z0.025=1.96

Q: A survey found that out of 900 workers, 150 said they were interrupted by frank phone calls. Find…

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Q: In a study of 150 randomly selected accidents that required treatment in an emergency room, 36%…

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Q: Of 380 randomly selected medical students, 21 said that they planned to work in a rural community…

A: Given that, Out Of 380 randomly selected medical students, 21 said that they planned to work in a…

Q: Of 380 randomly selected medical​ students, 21 said that they planned to work in a rural community.…

A: Given that 380 randomly selected medical​ students, 21 said that they planned to work in a rural…

Q: Find a 95% confidence interval for the proportion of renters.

A: It is given that  Favourable cases, X = 360 Sample size, n = 600 Confidence interval = 95%

Q: In a recent poll, 150 people were asked if they liked dogs, and 55% said they did. Find the margin…

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Q: What is the margin of error for a 90% confidence interval?

A: It is given that Sample size n = 850 Number of residents support property tax, X = 410 The critical…

Q: In a survey of 7100 t.v views, 40% said they watch network news programs. Find the margin of error…

A: Solution: From the given information, p-hat=0.40 and n=7100. The confidence level is 0.95.

Q: In a recent poll, 240 people were asked if they liked dogs, and 32% said they did. Find the margin…

A: Find z-critical value:…

Q: In a recent polI, 200 people were asked if they liked dogs, and 15% said they did. Find the margin…

A: From the provided information, Sample size (n) = 200 15% people said they like dogs that is p̂ =…

Q: Of 91 adults selected randomly from one town, 60 have health insurance. Find a 90% confidence…

A: From the provided information, Sample size (n) = 91 Out of which 60 have health insurance. Sample…

Q: In a poll of 2,500 likely voters, 966 say that the Philippines spend too little on education. Find…

A: Ans- Given the level of confidence interval   90 %                                        Then   α =…

Q: It was observed that 30 of the 100 randomly selected students smoked. Find the confidence interval…

A: It is given that, 30 out of 100 randomly selected students smoked i.e. proportion of the student who…

Q: In a random sample of 145 students, we find that 53% have attended a baseball game at some point in…

A: Given,sample size (n)=145sample proportion(p^)=0.53α=1-0.95=0.05α2 =0.025z0.025 =1.96

Q: Out of 500 people sampled, 455 had kids. The best point estimate for p is . The margin of error…

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Q: Why is a 99% confidence interval wider than a 95% confidence interval?

A: The confidence interval formula is sample statistic±Margin of error. The margin of error is the…

Q: In a sample of 600 Ottawa families, it is found that 360 rent their dwellings while 240 own their…

A: It is given that sample size (n) is 360 and x is 240.

Q: in a random sample of 192 college students, 129 had part-time jobs. Find the margin of error for the…

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Q: State the equation for the 95% confidence interval?

A: The equation for confidence interval can be stated as: Here x̅ is the sample mean, Zα/2 is the…

Q: A random survey of 36 airline passengers indicates that twelve have never flown before. Find a 95%…

A: We have given that,  Sample size (n) = 36 and favorable cases         (X) = 12 Then,  We Will find…

Q: In a sample of 900 people, 378 say they snooze the alarm more than once in the morning. Find a 95%…

A: Given,   The sample proportion is,

Q: Find a 90% confidence interval for the true proportion of people that eat frog legs, if in a sample…

A: Given, n = 732 p = 0.65 1 - α = 0.90α = 0.1α2 = 0.05   To find, 90% confidence interval for the true…

Q: In a sample of 95 recommendations, it is found that 56% of them made money. Determine the upper…

A: Proportion is almost similar to the concept of probability. Proportion is a fraction of population…

Q: In a random sample of 250 students who enrolled in Science, 150 took notes during classes. Find an…

A: Given that n=250,x =150,alpha =0.05 Find an approximate 95% confidence interval for the population…

Q: In a survey of 32 students at a local high school, 17 support changing the schools mascot. Find the…

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Q: In a recent poll, 110 people were asked if they liked dogs, and 40% said they did. Find the margin…

A: For 99% confidence intervalα=1-CI=1-0.99=0.01So, zα2=z0.012=z0.005=2.576

Q: Which of the below is the correct calculation of the 95¥% confidence interval?

A: Given that sample size n = 670 And sample proportion = 0.85 The critical value of Z at 95%…

Q: A recent study of 750 internet users in Europe found that 35% of internet users were women. What is…

A: It is given that the study of 750 internet users in Europe found that 35% of internet users were…

Q: Wildlife biologists inspect 200 deer taken by hunters and find 45 of them carrying Lyme disease…

A: Given; x=45n=200Then the sample proportion is given by;p^=45200=0.225The level of significance…

Q: In a recent poll, 410 people were asked if they liked dogs, and 44% said they did. Find the margin…

A: n = 410 p^=0.44 Confidence interval = 95%

Q: In a poll of 2,300 likely voters, 966 say that the Philippines spend too little on education. Find…

A: We have given that the sample size n = 2300, favourable cases X =966 and sample proportion p =…

Q: When 258 college students are randomly selected and surveyed, it is found that 106 own a car. Find a…

A: The provided information is: It is given that 106 college students (s) own a car among 258 college…

Q: 2. A survey found that out of 900 workers, 150 said that they were interrupted by frank phone calls.…

A: In question, We have given the number of favorable cases 150 and sample size 900 then we'll find 95%…

Q: Of 380 randomly selected medical students, 21 said that they planned to work in a rural community.…

A: Here we need to construct a 95% confidence interval for the population proportion. Here the sample…

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.