in cats, blood-type A results from an allele (IA) that is dominant over an allele (iB) that produces blood-type B. There is no O blood type. The blood types of male and female cats that were mated and the blood types of their kittens follow. Give the most likely genotypes for the parents of each litter. Male parent Female parent Kittens 4 with type A, 3 with type B 6 with type B 8 with type A 7 with type A, 2 with type B 10 with type A 4 with type A, 1 with type B a. A в b. B B C. B A d. A A e. A A f. A B
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- In cats, blood-type A results from an allele (IA) that is dominant over an allele (iB) that produces blood-type B. There is no O blood type. The blood types of male and female cats that were mated and the blood types of their kittens follow. Give the most likely genotypes for the parents of each litter. Male parent Female parent Kittens a. A B 4 with type A, 3 with type B b. B B 6 with type B c. B A 8 with type A d. A A 7 with type A, 2 with type B e. A A 10 with type A f. A B 4 with type A, 1 with type BAssume that blood type is inherited as A and B dominant over O, but A and B are codominantover each other. Genotypes (IA IA) and (IA i) are then phenotypically type A, genotypes (IB IB) and(IB i) are type B, genotype (IA IB) is type AB, and genotype (i i) is type O blood. A man with bloodtype IA IA marries a woman with type AB blood. What are the genotypic and phenotypic ratios ofthe children?With regard to the ABO blood types in humans, determine thegenotypes of the male parent and female parent: Male parent: blood type B whose mother was type OFemale parent: blood type A whose father was type B Predict the blood types of the offspring that this couple may have and the expected ratio of each.
- Write the genotype for each person based on : -Homozygous for B allele -Heterozygous for A allele -Type O -Type A and had a type O parent -Type AB -Blood that can be donated to anybody -Can only received blood from a type O donor There is a couple, the blood type of a male is A+ and the female is o+. What are all the possible blood types of their children in the future? Illustrate the inheritance in a Punnett Square showing all the possible blood types from the offspring of the male and female.In rabbits, black hair is dependent on a dominant allele B, and brown upon arecessive allele b. Short-hair is due to dominant allele S and long hair to arecessive allele s. If a true-breeding black short haired male is mated with abrown, long-haired female, what will their offspring look like? What will be the genotypes of the offspring?Three coat-color patterns that occur in some breeds of horses aretermed cremello (beige), chestnut (brown), and palomino (goldenwith light mane and tail). If two palomino horses are mated, theyproduce about 1/4 cremello, 1/4 chestnut, and 1/2 palomino offspring. In contrast, cremello horses and chestnut horses breed true.(In other words, two cremello horses will produce only cremellooffspring, and two chestnut horses will produce only chestnut offspring.) Explain this pattern of inheritance.
- In cats, the allele (B) produces black color but (b) producesyellow color. These alleles are co‐dominant to each other. Aheterozygote produces a tortoise‐shell color. The alleles (B)and (b) are sex‐linked as well. Cross a tortoise‐shell femalewith a yellow male. What percent of their offspring will be yellow? What percent of their offspring will be black? What percent of their offspring will be tortoise shell?. For several years, Hans Nachtsheim investigated an inherited anomaly of the white blood cells of rabbits. Thisanomaly, termed the Pelger anomaly, is the arrest ofthe segmentation of the nuclei of certain white cells. Thisanomaly does not appear to seriously burden the rabbits.a. When rabbits showing the Pelger anomaly were matedwith rabbits from a true-breeding normal stock,Nachtsheim counted 217 offspring showing the Pelgeranomaly and 237 normal progeny. What is the geneticbasis of the Pelger anomaly?b. When rabbits with the Pelger anomaly were matedwith each other, Nachtsheim found 223 normal progeny,439 with the Pelger anomaly, and 39 extremely abnormalprogeny. These very abnormal progeny not only haddefective white blood cells, but also showed severedeformities of the skeletal system; almost all of themdied soon after birth. In genetic terms, what do yousuppose these extremely defective rabbits represented?Why were there only 39 of them?c. What additional experimental evidence…In the multiple-allele series that determines coat color inrabbits, c+ encodes agouti, cch encodes chinchilla (a beigecoat color), and ch encodes Himalayan. Dominance is inthe order c+ > cch > ch. In a cross of c+/cch × cch/ch, whatproportion of progeny will be chinchilla?
- In guinea pigs, short hair is dominant to long hair. Also in guinea pigs, black eyes aredominant to red eyes. A male guinea pig that is heterozygous for both traits is crossedwith a female that is long haired and red eyed. What are the expected phenotypes oftheir offspring? Provide the phenotypic ratio as well.In the Bombay phenotype, a homozygous recessive individual hh appears to have blood type O because she is unable to produce the H substance, which is required to make the A or B blood-type antigens. HH or Hh individuals normally produce H substance. What is the probability that a child will test as type A blood from parents with the following genotypes? IAIO Hh X IBIO Hh 3/16 7/16 1/2 1/4 3/4Mexican hairless dogs have little hair and few teeth. When aMexican hairless is mated to another breed of dog, about half ofthe puppies are hairless. When two Mexican hairless dogs aremated to each other, about 1/3 of the surviving puppies have hairand about 2/3 of the surviving puppies are hairless. However,about two out of eight puppies from this type of cross are borngrossly deformed and do not survive. Explain this pattern ofinheritance.