In certain composition ranges of mixtures of ethylene tetrachloride (C2Cl4), isopropyl alcohol, and water separate, if given enough time, into two liquid phases. A table of eqilibirium data is shown below: The left-hand side of the table shows the compositions in the lower layer and the right-hand side shows the compositions of the upper layer in equilibrium with that composition. In the process for today, 100 lbs of a composition of 40%-by-mass C2Cl4, 38%-by-mass isopropyl alcohol and 22%-by-mass water is initially mixed and then allowed to separate.Lower layer%-by-massUpperlayer%-by-massC2Cl4isopropyl alcoholwaterC2Cl4isopropyl alcoholwater1000000100945113366881022149308215335461976204203812a. Draw a schematic of this process.b. Based on your drawing, conduct a degree of freedom analysis. Is this problem solvable? Justify your answer.c. Assuming that the lower level contains 10%-by-mass isopropyl alcohol, what is the mass of each of the two phases formed?

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Asked Feb 23, 2019
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In certain composition ranges of mixtures of ethylene tetrachloride (C2Cl4), isopropyl alcohol, and water separate, if given enough time, into two liquid phases. A table of eqilibirium data is shown below: The left-hand side of the table shows the compositions in the lower layer and the right-hand side shows the compositions of the upper layer in equilibrium with that composition. In the process for today, 100 lbs of a composition of 40%-by-mass C2Cl4, 38%-by-mass isopropyl alcohol and 22%-by-mass water is initially mixed and then allowed to separate.

Lower layer %-by-mass Upper layer %-by-mass
C2Cl4 isopropyl alcohol water C2Cl4 isopropyl alcohol water
100 0 0 0 0 100
94 5 1 1 33 66
88 10 2 21 49 30
82 15 3 35 46 19
76 20 4 20 38 12

a. Draw a schematic of this process.

b. Based on your drawing, conduct a degree of freedom analysis. Is this problem solvable? Justify your answer.

c. Assuming that the lower level contains 10%-by-mass isopropyl alcohol, what is the mass of each of the two phases formed?

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Expert Answer

Step 1

Part (a)

The basis of the calculation is taken as 100 lbs of feed mixture containing 40 mass% C2Cl4, 38% C3H8O and 22% H2O.

Let, m1 be the mass of upper layer and m2 be the mass of lower layer.

x1A is the mass fraction of C2Cl4, x1B is the mass fraction of C3H8O, and x1C is the mass fraction of H2O  in upper layer.

x2A is the mass fraction of C2Cl4, x2B is the mass fraction of C3H8O, and x2C is the mass fraction of H2O  in lower layer.

The schematic diagram of the given process is shown below.

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Step 2

Part (b)

 

Degree of freedom helps in determining the number of variables that must be specified so that the remaining unknowns can be evaluated. The formula used to calculate degree of freedom (DF) is written below.

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Step 3

There are total 8 unknown variables present. These are, m1, m2, x1A, x1B, x1C, x2A, x2B, and  x2C.

There are 3 independent equations, one for each of the species, 2 mole fraction summations and 2 equ...

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