In dolphins, gray (G) is dominant to black (g), Sleek (S) is dominant to pudgy (s) and friendly (F) is dominant to mean (f). All loci are autosomal. Pure-breeding black, sleek, meandolphins were mated to pure-breeding gray, pudgy, friendly dolphins. The F1 were testcrossed. Based on the map below and a coefficient of coincidence of 0.75, determine thefrequency of each phenotype in the testcross progeny. Round each answer to 5 decimal digits.ColorTBody TypeDisposition10CM13CM1) What is the frequency of gray, sleek testcross progeny?2) What is the frequency of gray, friendly testcross progeny?3) What is the frequency of black, friendly testcross progeny?4) What is the frequency of black, pudgy, mean testcross progeny?5) What is the frequency of gray, pudgy, friendly testcross progeny?6) What is the frequency of gray, sleek, mean testcross progeny?7) What is the frequency of pudgy, friendly testcross progeny?8) What is the frequency of pudgy, mean testcross progeny?

Formulas for three point test cross - A. Distance between two genes = (#progenies obtained by SCO…

1) What is the frequency of gray, sleek testcross progeny? 2) What is the frequency of gray, friendly testcross progeny? 3) What is the frequency of black, friendly testcross progeny? 4) What is the frequency of black, pudgy, mean testcross progeny? 5) What is the frequency of gray, pudgy, friendly testcross progeny?

1) What is the frequency of gray, sleek testcross progeny? 2) What is the frequency of gray, friendly testcross progeny? 3) What is the frequency of black, friendly testcross progeny? 4) What is the frequency of black, pudgy, mean testcross progeny? 5) What is the frequency of gray, pudgy, friendly testcross progeny?

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter5: The Inheritance Of Complex Traits

Section: Chapter Questions

Problem 5QP: As it turned out, one of the tallest Potsdam Guards had an unquenchable attraction to short women....

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Hemophilia and color blindness are both recessive conditions caused by genes on the X chromosome. To calculate the recombination frequency between the two genes, you draw a large number of pedigrees that include grandfathers with both hemophilia and color blindness, their daughters (who presumably have one chromosome with two normal alleles and one chromosome with two mutant alleles), and the daughters sons. Analyzing all the pedigrees together shows that 25 grandsons have both color blindness and hemophilia, 24 have neither of the traits, 1 has color blindness only, and 1 has hemophilia only. How many centimorgans (map units) separate the hemophilia locus from the locus for color blindness?
Two pure-breeding parents produced a heterozygous female offspring (AaBb) that was then testcrossed with an aabb male. The offspring produced from the testcross included 50 AaBb, 450 Aabb, 450 aaBb, 50 aabb individuals. Describe how you can tell if these two genes are linked or unlinked (What ratio would you expect to see from the testcross if they were not linked?). What were the genotypes of the original parents that produced the heterozygous female? What is the genetic map distance between the two genes?
In terms of a chi-square analysis, what ratio would be tested for the offspring of a monohybrid cross involving a pure-breeding dominant condition mated with a pure-breeding recessive condition?
Complete a Punnett square for a genetic cross of two truebreeding Portuguese water dogs—one with a black, wavy coat (homozygous dominant, BBWW) and one with a brown, curly coat (homozygous recessive, bbww). What is the phenotype ratio of their offspring (F1)? Now ﬁll out another Punnett square, crossing two of the offspring. What is the phenotype ratio of the F2 generation?
Guinea pigs have coats that are either rough or smooth. Rough coats are dominant, so they are represented by (R), and smooth coats are recessive, so they are represented by (r). If we crossed a homozygous rough-coated guinea pig with a smooth-coated guinea pig, what are the phenotypic and genotypic ratios?
Individuals of genotype AaBb were mated to individuals of genotype aabb. One thousand offspring were counted, with the following results: 474 Aabb, 480 aaBb, 20 AaBb, and 26 aabb. What type of cross is it? Are these locilinked? What are the two parental classes and the two recombinant classes of offspring? What is the percentage of recombination between these two loci? How many map units apart are they?
Two true-breeding varieties of maize, one 11 cm high and the other 47 cm high were crossed and the resultant F1 hybrids were then crossed to generate the F2. In the F2 there were a total of 13,923 plants with a continuous variation in heights between the two extremes and with only 3 plants as large as 47 cm high and 5 plants of 11 cm high. What would be the size and genotype of the F1 from a cross between a true-breeding 11 cm plant and a true-breeding 47 cm plant?
Two true-breeding varieties of maize, one 11 cm high and the other 47 cm high were crossed and the resultant F1 hybrids were then crossed to generate the F2 . In the F2 there were a total of 13,923 plants with a continuous variation in heights between the two extremes and with only 3 plants as large as 47 cm high and 5 plants of 11 cm high. What would be the size and genotype of the F1 from a cross between a true-breeding 11 cm plant and a true-breeding 47 cm plant? Please answer the following problem & EXPLAIN your answer showing ALL WORKING.
When roan cattle are mated, 25% of the offspring are red, 50% are roan, and 25% are white. Upon examination, it can be seen that the coat of a roan cow consists of both red and white hairs. What were the original parental genotypes?
Two true-breeding varieties of maize, one 11 cm high and the other 47 cm high were crossed and the resultant F1 hybrids were then crossed to generate the F2 . In the F2 there were a total of 13,923 plants with a continuous variation in heights between the two extremes and with only 3 plants as large as 47 cm high and 5 plants of 11 cm high.SO In a cross between a 29cm plant and a 20cm plant what would be the genotypes giving the smallest number of different phenotypes? specify the phenotypes observed.
In a three-point testcross such as this one, why aren’t the F1 and the tester considered to be parental in calculating recombination? (They are parents in one sense.)
A series of three-point testcrosses is made to determine the genetic map order of seven linked allele pairs: A/a, B/b, G/g, H/h, Q/q, R/r, and Y/y.From each cross between a triply heterozygous parent listed below, two recombinant classes were noticed as the least frequent among all 8 progeny classes, and are listed at the right in the table. A. For each testcross write the genotype of the F1 heterozygous parent. F1 Parental Phenotype Least frequent F2 Phenotype 1.AHB&ahb AHb & ahB 2.RYh&ryH RYH & ryh 3.BhY&bHy Bhy & bHY 4.qYB&Qyb qYb & QyB 5.AbQ&aBq Abq & aBQ 6.ghR&GHr ghr & GHR B. Write the unified map order of these genes, showing your reasoning.