In each of Exercises, use the one-proportion plus-four z-interval procedure to find the required confidence interval. Interpret your results. Social Networking. A Pew Internet&American Life Project examined Internet social networking. Among a sample of 929 online adults 18–29 years old, 836 said they use social networking sites. Determine a 95% confidence interval for the percentage of all online adults 18–29 years old who use social networking sites.

Q: Out of 100 people sampled, 16 have tried marijuana. Based on this, construct a 95% confidence…

A: Obtain the 95% confidence interval for the true population proportion of people who have tried…

Q: In a​ poll, 51​% of the people polled answered yes to the question​ "Are you in favor of the death…

A:

Q: In a survey, the planning value for the population proportion is .25. How large a sample should be…

A: Solution: It is given that the planning value for the population proportion is 0.25. The confidence…

Q: Della has over 500 songs on her mobile phone, and she wants to estimate what proportion of the songs…

A: The formula for the confidence interval is , CI=p^± Z*p^1-p^n Where,  p^=the proportion in sample…

Q: 3. You want to find out the percent of people who use an iPhone, so you survey 120 random adults, of…

A: Here we need to construct a 95% confidence interval for the population proportion.

Q: find the margin of error for a sample mean, given n=16, s=4, Xbar=17. for a 95% confidence interval.

A: The margin of error for sample mean is given by,

Q: The County Development Agency does a survey of all the mobile home manufacturers in Clarion County…

A: X̄ = $13,550, σ = $2,000, n = 25,

Q: Campus athletics is interested in the proportion of registered students living on campus who play…

A: The 95% confidence interval is (0.12, 0.18).

Q: In each of Exercises, use the two-proportions plusfour z-interval procedure to find the required…

A:

Q: T.J. wants to estimate the percentage of college students who have taken out student loans. He…

A:

Q: The. Nielsen television ratings used a random sample of 2,000 homes and found that 45% of the homes…

A:

Q: Find the condence level and a for a. a 90% confidence interval.b. a 99% confidence interval.

A: a.The confidence level and α for a 90% confidence interval is obtained below:The confidence level is…

Q: (a) How many subjects are needed to estimate the mean number of books read the previous year within…

A:

Q: Construct the 94% confidence interval estimate of the population proportion ? if the sample size is…

A:

Q: In a​ poll, 51​% of the people polled answered yes to the question​ "Are you in favor of the death…

A: The following information has been provided: p^=0.51E=0.03 The level of significance is : α=1-0.94…

Q: In one city, 59.6% of the 1500 students surveyed said they eat at the school cafeteria. Find the 95%…

A: Given, Sample size=n=1500 p^=0.596 α=0.05

Q: ccording to the data, calculate a 90% confidence interval for the sample mean. What was the T Score…

A: Solution: n= 30 Sample size ∑xi=642 x=∑xin=64230=21.4 Sample mean s2=∑(xi-x)2n-1=56.52414 Sample…

Q: In a​ poll, 6969​% of the people polled answered yes to the question​ "Are you in favor of the death…

A: Obtain the value of the minimum number of surveyed people. The value of the minimum number of…

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: The sample size n=92. The sample proportion is 61/92. The absolute value of Zα/2 is 1.645 using the…

Q: Find the confidence level and α for a. an 85% confidence interval. b. a 95% confidence interval.

A:

Q: In a four-year psychedelic-mushroom experiment, 93 of the 300 subjects reported experiencing “strong…

A: Given information- We have given that 93 of the 300 subjects reported experiencing “strong or…

Q: In each of Exercises, use the one-proportion plus-four z-interval procedure to find the required…

A:

Q: The statistics department is interested in estimating the proportion of students who have majored in…

A: Here we need to find the required sample size to estimate the proportion of students who majored…

Q: s. Calculate the point estimate and confidence interval with a 2.5 mph margin of error.

A: Jeff wants to estimate the average speed of his fastball. He borrows a velocity detector from the…

Q: In each of Exercises, use the technology of your choice to decide whether applying the t-interval…

A: The sample size (n) 10 is small, therefore, the t-interval procedure to obtain a confidence interval…

Q: In a survey, the planning value for the population proportion is .25. How large a sample should be…

A: We have to find sample size..

Q: Which distribution (z or t) should you use to construct a confidence interval and why? Construct a…

A: “Since you have posted a question with multiple sub-parts, we will solve first three subparts for…

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: It is given that n=195 and x=162. The sample proportion is 162/195 = 0.8308 The sample size is 195…

Q: Is 12 minutes the margin of error for this 95% confidence interval v [Select ]

A: The 95% confidence interval for the average arrival time before departure for all air travellers is…

Q: Refer to the accompanying data set of 20 randomly selected presidents. Treat the data as a sample…

A: Given that,

Q: What Z score would be used to construct a 90% confidence level? Is it ... a. 1.65 b. 2.33 c.…

A: Confidence Level = 90 Significance Level = α = (100-90)% = 0.1 Critical value = z* = 1.65   […

Q: Find the confidence level and a for an 88% confidence interval.

A: Here use confidence level and significance level as alternative of each other

Q: In 2017, the CDC administered the Youth Risk Behavior Survey (YRBS) to a random sample of 14,795…

A: Obtain the 99% confidence interval for the proportion of the high school students have been cyber…

Q: At one large college, 1867 out of the 2500 students surveyed said they plan to take another science…

A: The known values are, p^=1,867/2,500=0.7468, n=2,500. Using standard normal table, the critical…

Q: Construct a confidence interval for the population proportion p. n ? 144, x ? 86, 90% confidence

A: Given: Confidence level = 0.90 Sample size (n) = 144 x = 86 Sample proportion p^=xn=86144

Q: Use the one-proportion plus-four z-interval procedure to find the required confidence interval.…

A: Condition: By rule of thumb, the confidence interval for the one-proportion plus-four z-interval…

Q: in a poll 51% of people polled answered yes to the question Are you in favor of the death penalty…

A: Given, p=0.51 M.E=0.02 α=1-0.94=0.06 As per z-distribution table, the critical value of z at 0.06…

Q: A website for car reviewssurveyeda random sample of 102car owners, and21wished they would have…

A:

Q: Find the confidence level and α for an 80​% confidence interval.

A: Given confidence level =80%

Q: Using your answers to parts (a) and (b), find a 95% confidence interval estimating the proportion of…

A: Here we need to construct a 95% confidence interval.

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: Given data, n=195 x=126 p=x/n=126/195=0.646   z-value at 95% confidence is Zc=1.96

Q: (d) Use the combined data of 80 students, construct a 95% confidence interval estimate of the…

A: Given that  Total students=n=40+40=80 Number of pass students=X=28+32=60

Q: Refer to the accompanying data set and construct a 90% confidence interval estimate of the mean…

A: The descriptive analysis is conducted using EXCEL. The software procedure is given below: Enter the…

Q: In a​ poll, 37​% of the people polled answered yes to the question​ "Are you in favor of the death…

A: Given information- Margin of error, E = 5% = 0.05 Confidence level, c = 96% We have given that 37​%…

Q: Visitors to Joshua Tree National Park were 94.14 percent confident that they would see a coyote.…

A: The confidence level is 94.14. 1-α=0.9414α=0.0586α2=0.02931-α2=0.9707 The critical value of…

Q: In a survey of 3299 adults aged 57 through 85​ years, it was found that 82.2​% of them used at least…

A: The confidence interval at 100 (1 – α) % confidence level gives us an interval estimate about the…

Q: In a​ poll, 69​% of the people polled answered yes to the question​ "Are you in favor of the death…

A: Given: Margin of errorE=0.02 Proportion of people who polled yes p^=0.69 The z value corresponding…

Q: Out of 300 people sampled, 78 had kids. Based on this, construct a 99% confidence interval for the…

A:

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.