In Exercises 11–18, find the slope of the function’s graph at the given point. Then find an equation for the line tangent to the graph there.11. ƒ(x) = x2 + 1, (2, 5)                    12. ƒ(x) = x - 2x2, (1, -1)13. g(x) = x/(x - 2) , (3, 3)                  14. 8/ x2 , (2, 2)15. h(t) = t3, (2, 8)                              16. h(t) = t3 + 3t, (1, 4)17. ƒ(x) = sqrt(x), (4, 2)                     18. ƒ(x) = sqrt(x + 1), (8,3).

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Asked Jan 13, 2020
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In Exercises 11–18, find the slope of the function’s graph at the given point. Then find an equation for the line tangent to the graph there.

11. ƒ(x) = x2 + 1, (2, 5)                    12. ƒ(x) = x - 2x2, (1, -1)

13. g(x) = x/(x - 2) , (3, 3)                  14. 8/ x2 , (2, 2)

15. h(t) = t3, (2, 8)                              16. h(t) = t3 + 3t, (1, 4)

17. ƒ(x) = sqrt(x), (4, 2)                     18. ƒ(x) = sqrt(x + 1), (8,3).

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