In Exercises 39–44, each function f(x) changes value when x changes from x, to xo + dx. Find a. the change Af = f(xo + dx) – f(xo); b. the value of the estimate df = f'(xo) dx; and c. the approximation error |Af – df|. y = f(x)/ Af = f(xo + dx) – f(x) df = f'(xo) dx (xo, F(xo)) dx Tangent 0| xo + dx 39. f(x) 3D х? + 2x, хо —D 1, 40. f(x) = 2x² + 4x – 3, xo = -1, dx = 0.1 41. f(x) = x³ - x, xo = 1, dx = 0.1 dx = 0.1 %3D 42. f(x) 3 х, Хо —D 1, dx %3D 0.1 43. f(x) — х 1, Хо —D 0.5, dx %3D0.1 44. f(x) 3D х3 — 2х + 3, Хо — 2, dx 3D 0.1

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.3: The Natural Exponential Function
Problem 51E
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In Exercises 39–44, each function f(x) changes value when x changes
from x, to xo + dx. Find
a. the change Af = f(xo + dx) – f(xo);
b. the value of the estimate df = f'(xo) dx; and
c. the approximation error |Af – df|.
y = f(x)/
Af = f(xo + dx) – f(x)
df = f'(xo) dx
(xo, F(xo))
dx
Tangent
0|
xo + dx
39. f(x) 3D х? + 2x, хо —D 1,
40. f(x) = 2x² + 4x – 3, xo = -1, dx = 0.1
41. f(x) = x³ - x, xo = 1, dx = 0.1
dx = 0.1
%3D
42. f(x) 3 х, Хо —D 1, dx %3D 0.1
43. f(x) — х 1, Хо —D 0.5, dx %3D0.1
44. f(x) 3D х3 — 2х + 3, Хо — 2, dx 3D 0.1
Transcribed Image Text:In Exercises 39–44, each function f(x) changes value when x changes from x, to xo + dx. Find a. the change Af = f(xo + dx) – f(xo); b. the value of the estimate df = f'(xo) dx; and c. the approximation error |Af – df|. y = f(x)/ Af = f(xo + dx) – f(x) df = f'(xo) dx (xo, F(xo)) dx Tangent 0| xo + dx 39. f(x) 3D х? + 2x, хо —D 1, 40. f(x) = 2x² + 4x – 3, xo = -1, dx = 0.1 41. f(x) = x³ - x, xo = 1, dx = 0.1 dx = 0.1 %3D 42. f(x) 3 х, Хо —D 1, dx %3D 0.1 43. f(x) — х 1, Хо —D 0.5, dx %3D0.1 44. f(x) 3D х3 — 2х + 3, Хо — 2, dx 3D 0.1
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