In fruit flies, red eyes (pr+_) are dominant to purple eyes (prpr) and normal wings (vg+_) are dominant to vestigial wings (vgvg). The genes are located on the same chromosome. A pure breeding red-eyed fly with vestigial wings was crossed with a pure-breeding purple-eyed fly with normal wings. All of the F1 progeny had a WT phenotype. •What isthe arrangement of alleles on the F1's chromosome? •The recombination frequency between the two genes is 15%. If an F1 individual were test crossed, what percentage of the progeny would you expect to have the WT phenotype?

In fruit flies, red eyes (pr+_) are dominant to purple eyes (prpr) and normal wings (vg+_) are dominant to vestigial wings (vgvg). The genes are located on the same chromosome. A pure breeding red-eyed fly with vestigial wings was crossed with a pure-breeding purple-eyed fly with normal wings. All of the F1 progeny had a WT phenotype. •What isthe arrangement of alleles on the F1's chromosome? •The recombination frequency between the two genes is 15%. If an F1 individual were test crossed, what percentage of the progeny would you expect to have the WT phenotype?

Name: In fruit flies, red eyes (pr+_) are dominant to purple eyes (prpr) and
Uploaded: 2024-03-20T06:43:04.000Z
Channel: Bartleby
Description: In fruit flies, red eyes (pr+_) are dominant to purple eyes (prpr) and normal wings (vg+_) are dominant to vestigial wings(vgvg). The genes are located on the same chromosome. A purebreeding red-eyed fly with vestigial wings was crossed with a pure-b

Concepts of Biology

1st Edition

ISBN:9781938168116

Author:Samantha Fowler, Rebecca Roush, James Wise

Publisher:Samantha Fowler, Rebecca Roush, James Wise

Chapter8: Patterns Of Inheritance

Section: Chapter Questions

Problem 2ACQ: Figure 8.10 In pea plants, purple flowers (P) are dominant to white (p), and yellow peas (Y) are...

See similar textbooks

Similar questions

Two genes of a flower, one controlling blue (B) versus white(b) petals and the other controlling round (R) versus oval (r)stamens, are linked and are 10 map units apart. You cross ahomozygous blue oval plant with a homozygous white round plant. The resulting F1 progeny are crossed with homozygouswhite oval plants, and 1,000 offspring plants are obtained.How many plants of each of the four phenotypes do youexpect?
You carry out a trihybrid cross (a cross in which the parental plants differ for three characters) between a tall pea plant with round, yellow seeds (TT RR YY) and a short pea plant with wrinkled, green seeds (tt rr yy). The parental plants are homozygous for all of the three characters. They are crossed to produce the F1 generation. Tall, round, and yellow are the dominant traits for each character. What will be the phenotypes of the F1 generation?
In butterflies, blue wings (B) are dominant over yellow wings (b), and stripes (S) are dominant over no stripes (s). These genes for these two characteristics assort independently. A homozygous butterfly with yellow wings and no stripes is crossed with a homozygous butterfly that has blue wings and stripes. Afterward, individuals from this F1 generation were crossed obtaining a total of 272 butterflies as follows: 135 blue-winged butterflies with stripes, 55 blue with no stripes, 57 yellow with stripes, and 25 yellow without stripes. What is the X2 value
. Consider the imaginary trait, bristles with split-ends, a trait hypothesized to be X-linked dominant. In a cross, the P1 virgin females were homozygous wild type while the males had bristles with split-ends. The F1 84 males were all wild type while the 90 females all had split-ends. In addition, the data for the F2 generation revealed 26 wild type males, 35 wild type females, 29 split-end males and 40 split-end females. Is this what is to be expected? Use chi-square to prove your position.
In four o’clock plants, many flower colors are observed. In a crossinvolving two true-breeding strains, one crimson and the otherwhite, all of the F1 generation were rose color. In the F2, four newphenotypes appeared along with the P1 and F1 parental colors.The following ratio was obtained: 1/16 crimson2/16 orange1/16 yellow2/16 magenta4/16 rose2/16 pale yellow4/16 white Propose an explanation for the inheritance of these flowercolors.
Three genes in fruit flies affect a particular trait, and at least one dominant allele of each gene is necessary to get a wild-type phenotype. a. What phenotypic ratio would you predict among the progeny if you crossed triply heterozygous flies? b. You cross a particular wild-type male in succession with three tester strains. In the cross with one tester strain (AA bb cc), only 1/4 of the progeny are wild type. In the crosses involving the other two tester strains (aa BB cc and aa bb CC), half of the progeny are wild type. What is the genotype of the wild-type male? (Pls help asap!!)
Polydactylism (extra digits) is due to a dominant autosomal allele, what is the likelihood that a couple with the normal number of digits have a son with polydactylism? Flower color in snapdragons is due to a gene with incomplete dominance: CRCR plants have red flowers, CRCW have pink flowers, and CWCW plants have white flowers. Which cross is expected to yield progeny that all have pink flowers? A couple is expressing a child, the man has hemophilia (a sex-linked blood disorder due to a recessive allele) and the woman is a carrier for this disorder. If they have a daughter, what is the likelihood that she will inherit hemophilia?
A fruit fly with a gray body and red eyes (genotype BbPp) is mated with a fly having a black and purple eyes (genotype bbpp). Show diagrammatically a genetic cross between the two flies and the possible genotypes and phenotypes of F1. What ratio of offspring would you expect if the body-colour and eye-colour genes are on different chromosome (unlinked)? When mating is actually carried out, most of the offspring look like the parents, but 3% have a gray body and purple eyes, and 3% have a black body and red eyes. Compare and discuss the observation with your answer in part (
Two genes control color in corn snakes as follows:O– B– snakes are brown, O– bb are orange, oo B– areblack, and oo bb are albino. An orange snake wasmated to a black snake, and a large number of F1progeny were obtained, all of which were brown.When the F1 snakes were mated to one another, theyproduced 100 brown offspring, 25 orange, 22 black,and 13 albino.a. What are the genotypes of the F1 snakes?b. What proportions of the different colors wouldhave been expected among the F2 snakes if the twoloci assort independently?
In watermelons, bitter fruit (B) is dominant over sweet fruit (b), andyellow spots (S) are dominant over no spots (s). The genes for these two characteristics assort independently. A homozygous plant that has bitter fruit and yellow spots is crossed with a homozygous plant that has sweet fruit and no spots. The F1 are intercrossed to produce the F2. Q. If an F1 plant is backcrossed with the bitter, yellow-spotted parent, what phenotypes and proportions are expected in the offspring?
In Drosophila, sepia colored eyes are due to a recessive allele s and red eyes are due to a dominant allele S. If females with sepia eyes are crossed with homozygous males with red eyes, what phenotypic proportions will F1 y F2 respectively?
Three fruit shapes are recognized in the summer squash (Cucurbita pepo): disk-shaped, elongated, and sphere shaped. A pure disk-shaped variety was crossed to a pure elongated variety. The F1 were all disk-shaped. Among 80 F2 there were 30 sphere-shaped, 5 elongated, and 45 disk-shaped. Keeping in mind this gene interaction, what phenotypic proportions are expected in the progeny of the sphere-shaped in F2 when crossed at random?