In humans, Tongue roller and widows peak are dominant over non-tongue roller and straight hairline.  A heterozygote in both regards (for both tongue roller and hairline) reproduces with a similar heterozygote (they have the same genotype as the other parent).  What is the chance of any one child having the same phenotypes as the parents?

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Asked Oct 29, 2019
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In humans, Tongue roller and widows peak are dominant over non-tongue roller and straight hairline.  A heterozygote in both regards (for both tongue roller and hairline) reproduces with a similar heterozygote (they have the same genotype as the other parent).  What is the chance of any one child having the same phenotypes as the parents? 

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Expert Answer

Step 1

Given that tongue roller and widows peak are dominant over non-tongue roller and straight hairline. Let us represent T as the allele for tongue roller and W for widow's peak. Genotype for a heterozygote for both the traits would be TtWw.

Step 2

When parents with the same phenotype are crossed, the Punnett\...

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Parents: TtWw X TtWw Gametes (same for both parents) TW, Tw, tW, tw TW Tw tW tw TW TTWW TTWW TtWW TtWw TtWw Tw TTWW TTWW Ttww tW TtWW TtWw ttWW ttWw TtWw Ttww ttWw tw ttww

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