IN MAY OF 2000, AN ARTICLE IN A JOURNAL REPORTS THAT 35% OF AMERICAN FATHERS RELY ON THEIR SPOUSE OR THE MOTHER OF THEIR CHILDREN TO RESEARCH HEALTHCARE OPTIONS FOR THIER FAMILY. A RESEARCHER CLAIMS THAT THE FIGURE IS RISEN OVER RECENT YEARS. A RANDOM SAMPLE PF 734 FATHERS YEILDED 285 WHO DID NOT PARTICIPATE IN HEALTHCARE RESEARCH FOR THIER CHILDEREN. TEST THE RESEARCHERS CLAIM AT THE 0.05 SIGNIFICANCE LEVEL. IDENTIFY THE POINT ESTIMATE, NULL HYPOTHESIS, ALTERNATIVE HYPOTHESIS, CRITICAL VALUE, TEST STATISTIC, P-VALUE, DRAW THE Z DISTRIBUTION, DECISION ABOUT THE NULL HYPOTHESIS, AND FINAL CONCLUSION THAT ADDRESSES THE ORIGINAL CLAIM. CREATE THE 90% CONFIDENCE INTERVAL THAT CONTAINS THE TRUE POPULATION PROPORTION. EXPLAIN HOW THE CI SUPPORTS YOUR DECISION ABOUT THE NULL HYPOTHESIS?

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Asked Nov 11, 2019
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IN MAY OF 2000, AN ARTICLE IN A JOURNAL REPORTS THAT 35% OF AMERICAN FATHERS RELY ON THEIR SPOUSE OR THE MOTHER OF THEIR CHILDREN TO RESEARCH HEALTHCARE OPTIONS FOR THIER FAMILY. A RESEARCHER CLAIMS THAT THE FIGURE IS RISEN OVER RECENT YEARS. A RANDOM SAMPLE PF 734 FATHERS YEILDED 285 WHO DID NOT PARTICIPATE IN HEALTHCARE RESEARCH FOR THIER CHILDEREN. TEST THE RESEARCHERS CLAIM AT THE 0.05 SIGNIFICANCE LEVEL. IDENTIFY THE POINT ESTIMATE, NULL HYPOTHESIS, ALTERNATIVE HYPOTHESIS, CRITICAL VALUE, TEST STATISTIC, P-VALUE, DRAW THE Z DISTRIBUTION, DECISION ABOUT THE NULL HYPOTHESIS, AND FINAL CONCLUSION THAT ADDRESSES THE ORIGINAL CLAIM. CREATE THE 90% CONFIDENCE INTERVAL THAT CONTAINS THE TRUE POPULATION PROPORTION. EXPLAIN HOW THE CI SUPPORTS YOUR DECISION ABOUT THE NULL HYPOTHESIS?

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Expert Answer

Step 1

Point estimate:

Here, p denotes the proportion of fathers who did not participate in healthcare research for their children.

The point estimate, p-hat is:

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285 734 0.3883

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Step 2

It is given that the population proportion; p is 0.35.

Null hypothesis: H0: p = 0.35.

Alternative hypothesis: H1: p > 0.35.

Step 3

Critical value:

It known that the level of significance is 0.05.

Enter the formula “=NORM.S.INV...

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