In Part C, we look at the following reaction:Fe3+ (aq) + SCN- (aq) ⇆ FeSCN2+ (aq)a. Write the equilibrium constant expression for the reaction if the equilibrium constant is 78.b. Does the equilibrium mixture contain more products or reactants?c. If more SCN- is added to the equilibrium mixture, will the red color of the mixture intensify or lessen? Explain.

Question
Asked Nov 21, 2019
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In Part C, we look at the following reaction:

Fe3+ (aq) + SCN- (aq) ⇆ FeSCN2+ (aq)

a. Write the equilibrium constant expression for the reaction if the equilibrium constant is 78.

b. Does the equilibrium mixture contain more products or reactants?

c. If more SCN- is added to the equilibrium mixture, will the red color of the mixture intensify or lessen? Explain.

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Expert Answer

Step 1

a)The given reaction is

 

Fe3t (aq)+ SCN (aq)S FeSCN2+ (aq)
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Fe3t (aq)+ SCN (aq)S FeSCN2+ (aq)

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Step 2

Equilibrium constant is ratio of concentration of products and reactants.

[products]
reactants
since the value of K, in the question is 78
FESCN2
78=
FeSCN
3+
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[products] reactants since the value of K, in the question is 78 FESCN2 78= FeSCN 3+

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Step 3

b)   Since the value of Kc is 78, it means that the reaction has almost reached completion. If Kc is much greater than 1 then it m...

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