In Question 10p of Chapter 4, the genotype of parents of litters with the following phenotypes was determined as "Bbdd x bbDd." How was this phenotype determined based on the genotype: a. ) 4 brown, 4 black, 4 yellow and 4 cream 4 brown (4 B_D_) , 4 black (4 B_dd), 4 yellow (4 bbD_), 4 cream (4 bbdd) Hoping to get feedback in the shortest possible time.

In Question 10p of Chapter 4, the genotype of parents of litters with the following phenotypes was determined as "Bbdd x bbDd." How was this phenotype determined based on the genotype: a. ) 4 brown, 4 black, 4 yellow and 4 cream 4 brown (4 B_D_) , 4 black (4 B_dd), 4 yellow (4 bbD_), 4 cream (4 bbdd) Hoping to get feedback in the shortest possible time.

Name: In Question 10p of Chapter 4, the genotype of parents of litters with
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Description: In Question 10p of Chapter 4, the genotype of parents of litters with the following phenotypes was determined as "Bbdd x bbDd." How was this phenotype determined based on the genotype:a. ) 4 brown, 4 black, 4 yellow and 4 cream4 brown (4 B_D_) , 4 bl

Biology 2e

2nd Edition

ISBN:9781947172517

Author:Matthew Douglas, Jung Choi, Mary Ann Clark

Publisher:Matthew Douglas, Jung Choi, Mary Ann Clark

Chapter12: Mendel's Experiments And Heredity

Section: Chapter Questions

Problem 16RQ: A farmer raises black and white chickens. To his surprise, when the first generation of eggs hatch...

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A farmer raises black and white chickens. To his surprise, when the first generation of eggs hatch all the chickens are black with white speckles throughout their feathers. What should the farmer expect when the eggs laid after interbreeding the speckled chickens hatch? All the offspring will be speckled 75% of the offspring will be speckled, and 25% will be black 50% of the offspring will be speckled, 25% will be black, and 25% will be white 50% of the offspring will be black and 50% of the offspring will be white.
When the F1 bees were backcrossed to the inbred resistant line produced 4 types of offspring in equal numbers: ¼ if the back-cross offspring showed the complete hygienic behavior pattern ¼ of the back-cross offspring showed none of the elements of hygienic behavior ¼ of the back-cross offspring would uncap the cells of the diseased larvae but these workers would not remove the diseased larvae ¼ of the back-cross offspring would remove the diseased larvae (once the experimenter had uncapped the cells of the diseased larvae) Is it possible that two gene loci are involved in the resistant behavior? Justify your answer.
) When the F1 bees were backcrossed to the inbred resistant line produced 4 types of offspring in equal numbers: ¼ if the back-cross offspring showed the complete hygienic behavior pattern ¼ of the back-cross offspring showed none of the elements of hygienic behavior ¼ of the back-cross offspring would uncap the cells of the diseased larvae but these workers would not remove the diseased larvae ¼ of the back-cross offspring would remove the diseased larvae (once the experimenter had uncapped the cells of the diseased larvae) Given the genetic model given in part d, do the backcross offspring in part c (from an F1 x resistant line) show evidence of linkage between the U and R gene loci? Give a reason for your answer.
Part 1 - With use of Punnett diagrams discuss how the results of experiments carried out by Austrian monk Gregor Mendel on pea plants brought about the Law of Dominance, the Law of Segregation, and the Law of Independent assortment. Part 2 - In humans, the gene that produces the disease Sickle Cell Anaemia is recessive to the gene for healthy haemoglobin production. a) How can two phenotypically healthy parents have a child who suffers from Sickle cell Anaemia? In your answer use suitable letters to show the genotypes of the parents and construct a Punnett diagram to show all the possibilities of the children's genotypes. b) Based on the outcome of your Punnett diagram, state and explain the probability of a child being a sufferer of Sickle Cell Anaemia and the probability of a child not suffering from the disease. c) If an individual who suffers from Sickle cell disease has a child with someone who is healthy (and not carrying the sickle cell gene), what is the probability that…
Can ypu answer ALL parts to this question Pigment of chicken feathers is regulated by two genes, the gene for feather pigment C, and a gene that inhibits pigment production, I. A mother chicken, who is heterozygous for gene c, and heterozygous for gene I, is crossed with a father chicken, who is homozygous recessive for the pigment gene, and heterozygous for gene I. Inhibition is dominant to uninhibited, pigmented feathers are dominant to unpigmented feathers. The inhibitor gene (I) will prevent expression of pigmented chicken feathers. Use the letters C, c, I, and i for the genes. C is for color and I is for inhibitor Enter your answer as a list of haplotypes separated by spaces such as AB ab Ab aB. Do not write a sentence. Do not list duplicate haplotypes. Alphabatize your haplotypes, e.g. Ab, not bA. A) What are the potential genotypes of the gametes produced by the mother for these two genes? B) What are the potential genotypes of the gametes produced by the father for…
20. 20.Which among the following statements is INCORRECT? A. Codominance is evident when a cross between organisms with two different phenotypes produces offspring that exhibits both parental traits because the alleles for each trait are neither completely dominant nor recessive B. Incomplete dominance is evident when a cross between a white carnation and a red carnation results in a pink carnation flower. C. Law of dominance state that if the alleles of a specific gene differ from each other, only one phenotype will be expressed while the other is masked D. The inheritance of one trait does not affect the inheritance of the other trait especially if the allele of the other trait is located in a different chromosome
Consider a situation where F1 is backcrossed with one of its parental lineage and we obtained A1H1/A2H2 : A2H1/A2H2 : A2H2/A2/H2: A1H2/A2H2 = 295 : 186 : 310 : 209, where A1 and A2 are alleles at a locus and H1 and H2 are alleles at the other locus. What is the recombination (genetic) distance between the two loci in centimorgans? A. 8.9 B. 22.5 C. 18.4 D. 50 E. 39.5
Doesn't the The F1 offspring being all LlDd means that the F1 centipedes have long legs and DARK colored bodies. Since D (dark) is dominant to to d (light)? Then if you drew a punnett swuare, wouldn't all the offspring being LlDd mean that none of the offspring have light bodies and short legs? So I don't understand the 25/4 fraction that you got for part a and where did the 1/16 come from?
Among a large population of 2 million gray mosquitoes, one mosquito is heterozygous for a body color gene; this mosquito has one gray allele and one blue allele. There is no selective advantage or disadvantage between gray and blue body color. All of the other mosquitoes carry two copies of the gray allele. A. What is the probability of fixation of the blue allele? B. If fixation happens to occur, how many generations is it likely to take? C. Qualitatively, how would the answers to parts A and B be affected if the blue allele conferred a slight survival advantage?
How many affected females and males does this pedigree show? (2) Who is the proband? (3) How many generations are included? (4) What kind of inheritance pattern is the disease-causing allele in this pedigree? Why? (5) Who have the same genotype as the proband? Why?
When the F1 bees were backcrossed to the inbred resistant line produced 4 types of offspring in equal numbers: ¼ if the back-cross offspring showed the complete hygienic behavior pattern¼ of the back-cross offspring showed none of the elements of hygienic behavior¼ of the back-cross offspring would uncap the cells of the diseased larvae but these workers would not remove the diseased larvae¼ of the back-cross offspring would remove the diseased larvae (once the experimenter had uncapped the cells of the diseased larvae) 1. Is it possible that two gene loci are involved in the resistant behavior? Show work.
In the experiment described in Figure 4.9, Morgan obtained awhite-eyed male fly in a population containing many red-eyedflies that he thought were true-breeding. The figure says that hecrossed this fly with a red-eyed female, and all the offspring hadred eyes. But actually this is not quite true. Morgan observed 1237red-eyed flies and 3 white-eyed males. Provide two or more explanationswhy he obtained 3 white-eyed males in the F1 generation.