In some recent studies it has been shown that women are more susceptible to torn anterior cruciate ligaments, or ACLs, than men when competing in similar sports (most notably in soccer and basketball).   Select the statement that explains why this disparity might exist.   The ACL of women is more elastic than the ACL of men.   The Young's modulus of women's ACLs is typically smaller than that of men's, resulting in more stress for the same amount of strain.   The cross-sectional area of the ACL is typically larger in men, and therefore experiences less strain for the same tensile force and Young's modulus.   The cross-sectional area of the ACL is typically smaller in women, and therefore experiences less stress for the same tensile force.

Q: A 61 cm long copper wire is clamped at one end and a stone weighing 2.2 kg is attached to the other…

A:

Q: Many caterpillars construct cocoons from silk, one of the strongest naturally occurring materials…

A: (a)Write the expression for young’s modulus of the material.

Q: A strand of dragline spider silk has a diameter of 6.0 μm, and can support a mass of 2.9 g.…

A: Required : Approximately how many copper wires would it take tosupport the same mass?

Q: What is the tension force in the wire shown below if it stretches 0.35 cm when tightened if young's…

A:

Q: The elastic limit of an alloy is 7.0 x 10% N/m². What is the minimum radius rmin of a 4.0 m long…

A:

Q: A1 (1.0) m long rod of cross-section 1.0x10 4 m2 is stretched by 537 um. What is the tensile stress…

A: Given, Length of rod,L=1 m Area of cross section,A=1×10-4m2 Change in length,∆L=537μm=5.37×10-4m…

Q: After a fall, a 88 kg rock climber finds himself dangling from the end of a rope that had been 16 m…

A: mass of climber = 88 kg Length of rope = 16 m diameter of rope = 8.5 mm radius of rope = 4.25 mm =…

Q: After a fall, a 85 kg rock climber finds himself dangling from the end of a rope that had been 18 m…

A: Given Data Mass of the rock climber is m=85 kg Length of the rope is l=18 m Diameter of the rope is…

Q: Use the stiffness method to calculate the member forces in the structure shown in Figure P1.9. E = 2…

A:

Q: Assume Young's modulus for bone is 1.50 x 1010 N/m2. The bone breaks if stress greater than a= 15086…

A: Given, Young's modulus = Stress =  Radius = 0.01 m

Q: If a 6.0 x 10^3 mm elastic cable of density 1.1 x 10^3 kg/m^3 is dangling, how much does the length…

A:

Q: Choose from the following choices the correct answer for the elastic modulus that describes the…

A: (i) A block of iron is sliding across a horizontal floor. The friction force between the block…

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A:

Q: What is the tension force in the wire shown below if it stretches 0.35 cm when tightened if young's…

A:

Q: A steel cable supports a lift that can carry a maximum load of 3000 Kg and it moves with an…

A: Given, cable can carry maximum load of 3000 kg     so mass=m=3000kg acceleation=6 m/sec2. Case 1:…

Q: The largest tendon in the body, the Achilles tendon, connects the calf muscle to the heel bone of…

A: Write the expression for young’s modulus of the material.

Q: What is the tension force in the wire shown below if it stretches 0.35 cm when tightened if young's…

A: Given : ∆L = 0.35 cm = 0.0035 m Y = 2 x 1011 N/m2 L = 2.5 m d = 0.30 cm = 0.003 m

Q: Humans can bite with a force of approximately 810 N. If a human tooth has the Young's modulus of…

A: SOlution: as given F = 810 N E = youngs modulus of bone= A = 1.5 cm2 = 1.5x10-4 m2 L = 1.5 cm =…

Q: The elastic limit of an alloy is 5.0×108 N/m2. What is the minimum radius ?min of a 9.0 m long wire…

A: ...

Q: After a fall, a 99 kg rock climber finds himself dangling from the end of a rope that had been 15 m…

A:

Q: A mass is hung from identical wires made of iron, lead, nickel, steel, and brass. Which wire will…

A:

Q: Assume Young's modulus for bone is 1.50 x 1010 N/m2. The bone breaks if stress greater than 1.50 x…

A: Given :      Young's modulus for bone, Y = 1.50*1010 N/m2       Stress to break the bone, S =…

Q: After a fall, a 100 kg rock climber finds himself dangling from the end of a rope that had been 16 m…

A:

Q: A disk between vertebrae in the spine is subjected to a shearing force of 625 N. Find its shear…

A: Bartleby's guidelines allowing answer only the first question

Q: After a fall, a 110 kg rock climber finds himself dangling from the end of a rope that had been 12 m…

A: mass of rock climber = 110 kg length of rope = 12 m diameter of rope = 7.7 mm streching in the rope…

Q: After a fall, a 94 kg rock climber finds himself dangling from the end of arope that had been 19 m…

A: Given value--- mass = 93 kg. initial length = 19 m. initial diameter = 8.4 mm. Change in length =…

Q: Assume that Young's Modulus for bone is 1.50 ✕ 1010 N/m2 and that the bone will fracture if more…

A: (a) Let us calculate the cross-sectional area, A of the bone:

Q: After a fall, a 90 kg rock climber finds himself dangling from the end of a rope that had been 16 m…

A: Part (a) extension or change in length= 3.3cm = 0.033 m  length = 16m  Strain = change in length ÷…

Q: Q4. When a tensile load (F) is applied to a solid homogeneous rod, the rod undergoes a change in…

A: Write the basic expressions related to stress and strain. Here, σ represents the stress, A…

Q: What is the Young's modulus (in N/m2) for this material? On a graph with a starting point of (0,0) a…

A: Young's modulus = stress÷strain Young's modulus = slope of stress-strain curve. Coordinates of curve…

Q: A person has 100 kg mass is suspended by his arms on a metallic bar. Determine the strain of the…

A: Given: Introduction: The young's modulus (Y) for a body is the measure of its strength. It is…

Q: Humans can bite with a force of approximately 795 N. If a human tooth has the Young's modulus of…

A: Young's modulus is defined as the ability of a material to withstand the change in length due to…

Q: After a fall, a 99 kg rock climber finds himself dangling from the end of a rope that had been 14 m…

A:

Q: A physics lab consists of a large ball attached to a wire. Students hold on to one end of the wire,…

A: Here given the wire of length 1.3 m and diameter 1mm. The young modulus is 20 × 10^10 N/m². The mass…

Q: Humans can bite with a force of approximately 807 N. If a human tooth has the Young's modulus of…

A: The equation for Young's modulus is given by, Y=σe  (1) Here, σ is the stress and e is the strain.…

Q: Assume Young's modulus for bone is 1.50 x 1010 N/m2. The bone breaks if stress greater than 0= 62780…

A: Young's modulus for the bone,  Breaking stress,  Effective radius of the bone,

Q: After a fall, a 94 kg rock climber finds himself dangling from the end of a rope that had been 16 m…

A:

Q: Dynamic climbing ropes are designed to be quite pliant, allowing a falling climber to slow down over…

A: The Young's Modulus is given by Y=StressStrain=FAStrain

Q: Find the mass of the picture hanging from a steel nail as shown, given that the nail bends only 1.80…

A: The force applied perpendicular to the L0 and parallel to the cross sectional area A can be…

Q: determine the change in the tooth's length

A: Given data:     The force applied during bite is: F = 796 N The cross-sectional area of tooth is: A…

Q: A particular human hair has a Young's modulus of 3.63×109 N/m2 and a diameter of 145 μm. If a 228 g…

A: Write the expression for Young’s modulus, and solve for the change in length of the hair.

Q: Assume Young’s modulus for bone is 1.40×1010 N/m2 . The bone breaks if stress greater than 1.50 ×…

A:

Q: After a fall, a 100 kg rock climber finds himself dangling from the end of a rope that had been 14 m…

A: GivenMass of rock climber, m=100 kgOrignal Length of rope, L=14 mDiameter of rope, D=10 mm=10×10-3…

Q: After a fall, a 110 kg rock climber finds himself dangling from the end of a rope that had been 14 m…

A:

Q: What hanging mass will stretch a 2.2-m-long, 0.34 mm - diameter steel wire by 1.2 mm? The Young's…

A:

Q: Assume Young's modulus for bone is 1.50 x 100 N/m². The bone breaks if stress greater than d= 40607…

A: Young modulus, Y=1.50× 1010 N/m2 Maximum stress, σ=40607 N/m2 Radius, r = 0.01 m

Q: The normal force of the ground on the foot can reach three times a runner's body weight when the…

A:

Mechanical Properties of Solids

There are three types of matter- solid, liquid and gas. Out of them, solids have a rigid shaped and size. The intermolecular forces of attractions in solids are greatest. Mechanical properties are the physical properties of a material which it shows, when it is provided with certain amount of force or load. These properties are to be kept in mind for various purposes. When a force is applied to an object, the object may or may not get deformed depending upon its elastic property. But every time the object develops a restoring force against the force applied. This is commonly known as stress. If the object changes its dimensions due to the force applied it develops strain ( which is the ratio of change in dimension to the original dimension).