In the 1989, Journal of Number Theory paper, N. Tzanakis and B. de Wegner showed that the largest of the 6 triangular numbers that are products of three consecutive integers is 258,474,216. What are the three consecutive integers? Solution: Let x represent the first consecutive integer, x+1 the second consecutive integer and x+2 the third consecutive integer, then x(x+1)(x+2) = 258,474,216 x(x² + 3x+2) = 258,474,216 x+3x²+2x=258,474,216 x+3x+2x-258, 474,216 = 0 Use the factor theorem, long division and the quadratic formula 4

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.1: Real Numbers
Problem 38E
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What is the factor theorem for this problem?
In the 1989, Journal of Number Theory paper, N. Tzanakis and B. de Wegner showed that the
largest of the 6 triangular numbers that are products of three consecutive integers is 258,474,216.
What are the three consecutive integers?
Solution: Let x represent the first consecutive integer, x+1 the second consecutive integer and
x+2 the third consecutive integer, then
x(x+1)(x+2) = 258,474,216
x(x² + 3x + 2) = 258,474,216
x+3x²+2x=258,474,216
x+3x²+2x-258,474,216 = 0
Use the factor theorem, long division and the quadratic formula
4
Transcribed Image Text:In the 1989, Journal of Number Theory paper, N. Tzanakis and B. de Wegner showed that the largest of the 6 triangular numbers that are products of three consecutive integers is 258,474,216. What are the three consecutive integers? Solution: Let x represent the first consecutive integer, x+1 the second consecutive integer and x+2 the third consecutive integer, then x(x+1)(x+2) = 258,474,216 x(x² + 3x + 2) = 258,474,216 x+3x²+2x=258,474,216 x+3x²+2x-258,474,216 = 0 Use the factor theorem, long division and the quadratic formula 4
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