In the diagram at the right, 49 and Z10 are complementary. 27 9; mZ8=41°. %3D (a) m/7 = 49 (b) m/10 = 31 In the diagram at the right, m/4 = (2x - 5)° and m/53(4x- 13)° (a) (b) m23 = (c) m/4 = (d) m25 = se the diagram at the right for Problems 5-6. If m/EFD= 19°, then m/BFC = 5. If m/BFC = (5x -9)° and m/EFD= (2x + 1)°, EF to then x=

Elementary Geometry For College Students, 7e
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Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
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In the diagram at the right, 49 and Z10 are complementary.
27 9; mZ8=41°.
%3D
(a)
m/7 =
49
(b)
m/10 =
31
In the diagram at the right, m/4 = (2x - 5)° and m/53(4x- 13)°
(a)
(b)
m23 =
(c)
m/4 =
(d)
m25 =
se the diagram at the right for Problems 5-6.
If m/EFD= 19°, then m/BFC =
5.
If m/BFC = (5x -9)° and m/EFD= (2x + 1)°,
EF to
then x=
Transcribed Image Text:In the diagram at the right, 49 and Z10 are complementary. 27 9; mZ8=41°. %3D (a) m/7 = 49 (b) m/10 = 31 In the diagram at the right, m/4 = (2x - 5)° and m/53(4x- 13)° (a) (b) m23 = (c) m/4 = (d) m25 = se the diagram at the right for Problems 5-6. If m/EFD= 19°, then m/BFC = 5. If m/BFC = (5x -9)° and m/EFD= (2x + 1)°, EF to then x=
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