In the electrolysis of aqueous sodium bromide, there are two possible anodic reactions: *2H2O(l) ——-> 02(g) + 4H+(aq) + 4e–, E° = 1.23V2Br–(aq) ——–> Br2(g) + 2e-2, E° = 1.08 VWhich reaction occurs at anode and why?
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In the
2H2O(l) ——-> 02(g) + 4H+(aq) + 4e–, E° = 1.23V
2Br–(aq) ——–> Br2(g) + 2e-2, E° = 1.08 V
Which reaction occurs at anode and why?
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