In the figure below, the change in internal energy of a gas that is taken from A to C along the blue path is +795 J. The work doneon the gas along the red path ABC is -485 J.B(a) How much energy must be added to the system by heat as it goes from A through B to C?(b) If the pressure at point A is five times that of point C, what is the work done on the system in going from C to D?(c) What is the energy exchanged with the surroundings by heat as the gas goes from C to A along the green path?(d) If the change in internal energy in going from point D to point A is +435 J, how much energy must be added to thesystem by heat as it goes from point C to point D?

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Asked Dec 8, 2019
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how to answer part a

In the figure below, the change in internal energy of a gas that is taken from A to C along the blue path is +795 J. The work done
on the gas along the red path ABC is -485 J.
B
(a) How much energy must be added to the system by heat as it goes from A through B to C?
(b) If the pressure at point A is five times that of point C, what is the work done on the system in going from C to D?
(c) What is the energy exchanged with the surroundings by heat as the gas goes from C to A along the green path?
(d) If the change in internal energy in going from point D to point A is +435 J, how much energy must be added to the
system by heat as it goes from point C to point D?
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In the figure below, the change in internal energy of a gas that is taken from A to C along the blue path is +795 J. The work done on the gas along the red path ABC is -485 J. B (a) How much energy must be added to the system by heat as it goes from A through B to C? (b) If the pressure at point A is five times that of point C, what is the work done on the system in going from C to D? (c) What is the energy exchanged with the surroundings by heat as the gas goes from C to A along the green path? (d) If the change in internal energy in going from point D to point A is +435 J, how much energy must be added to the system by heat as it goes from point C to point D?

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Expert Answer

Step 1

Given,

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Change in internal energy,AU4¬c =+795 J Work done on the gas, W =-485 J ABC

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Step 2

Part (a):

By using 1st law of thermodynamics we can get,

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AU = Q-W Q = AU +W where, AU = Change in internal Energy Q =Heat Supplied W = Work done by the gas

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Step 3

Since the work is done on the gas which is negative so work done by the gas will ...

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Work done by the gas=-(Work done on the gas) W =-(-485)= 485 J Q = AU +W Q = 795+ 485 Q= 1280 J

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