In the lab you weigh 12.54 g of NaCl how much water do you need to dissolve the NaCl and make a stock solution of 5.12 M? Give your answer in mL. To further dilute the solution to 100.0 mL of 0.125 M, how much of the stock solution do you need?

Q: The solubility of a specific salt is 0.5 g/mL, what is maximum amount in grams of this salt you can…

A: Given, solubility of specific salt = 0.5 g ml-1 volume= 156 ml mass=?

Q: 2. In Part A of this experiment you will prepare 0.1 M solutions of sodium carbonate (NazCO3),…

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Q: Use floating decimal in your solutions but express all final answers to four (4) decimal places and…

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Q: 1. A blood serum sample is analyzed and found to contain 102.5 µg Ca²*/mL serum. The density of the…

A: 3) Given that: Molarity of Cr3+ = 0.125 M Molarity of MnO4- = 0.200 M Volume of MnO4- = 12.00 mL

Q: For the titration of your sample you put 0.1039 g of Aspirin in your flask.  Pretend that the…

A: Mass of aspirin in sample =0.1039 gConcentration of standardized NaOH solution = 0.1000 MMolar mass…

Q: 00.0 mL of a 0.780 M solution of KBr is diluted to 500.0 mL. What is the new concentration of the…

A: Given that:        Initial concentration of the KBr solution = 0.780 M                    Initial…

Q: In this lab, stock solution A has an Fe2+ content of 0.0100 g/L. A student prepares a new sample…

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Q: Your protocol calls for a 0.15MM NaCl solution. How would you dilute your 3M NaCl solution to 0.15M…

A: 11) The total volume of the solution is 500μL(0.0005L) The concentration of the solution is 3M. We…

Q: What volume, in mL, of a 0.35 M Mg(NO3)2 aqueous solution contains 87 g of Mg(NO3)2?

A: Definition of Molarity is, Molarity is the number of moles of solute dissolve in one litre of the…

Q: A 50.0 mL portion of a stock solution was diluted to 500 mL. If the resulting solution was 1.14 M,…

A: Given data contains, Initial volume is 50.0 mL=0.05 L. Final volume is 500 mL=0.5 L. Initial…

Q: To what volume (in mL) would you need to dilute 20.0 mL of a 1.40 M solution of LiCN to make a…

A: Given  Volume ( V1)         = 20 mL  Molarity ( M1)      = 1.40 M  Molarity ( M2)     = 0.0900 M…

Q: 2. Determine the concentration of a diluted solution of sodium chloride that was prepared by…

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Q: Maria needs to dilute a stock solution of 16.0 M hydrochloric acid (HCI) for an experiment. If she…

A: We have a 5 mL of HCl solution having 16.0 M concentration...now, the final concentration of the…

Q: You have a stock solution of NaOH which is 0.1 M. if you wanted to prepare 5 mL of 0.057 M NaOH, how…

A: Dilution of the solution: On dilution of the solution with the pure water, the mole of solute…

Q: In Part A of this experiment you will prepare 0.1 M solutions of sodium carbonate (Na2CO3), sodium…

A: Molarity: The number of moles of solute present per liter of the solution is known as molarity.…

Q: Use the References to access important values if needed for this question. Two beakers are placed in…

A: Introduction  The most practical way to express a solute's concentration in a particular solution is…

Q: You take 5.0 mL of a 1.50 M solution of sucrose and dilute it to 250.0 mL. what is the mass of…

A: First use dilutuon formula to get the Final molarity after dilutuon  Then use formula…

Q: What is the dilution factor when 100 ul is added to a final volume of 5ml?

A: Since the units of initial volume is given ul instead of µl. Hence I'm assuming it to be µl i.e…

Q: What is the volume of a 2.34 M NaOH solution needed to make 150.0 mL of a 0.800 M NaOH solution

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Q: For the following, use the relation of M1V1 = M2V2, where M represents the molarity of the solution,…

A: Given that -  Mass of NaCl = 5.84 g  Volume of Solution = 100 mL  Molarity of first diluted Solution…

Q: At your next lab assignment, you are instructed to prepare 250 mL of 0.500 mol/L HCl by dilution of…

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Q: A 50.0 mL aqueous stock solution of 0.67 M HCl is diluted to a final volume of 188.1 mL. What is the…

A: The volume of stock solution before dilution (Vi) = 50.0 mL The molarity of stock solution before…

Q: What is the concentration, in ppm, if 0.9081 grams of Calcium chloride is dissolved in 250.0 ml of…

A: 1 ppm (parts per million) is the 1 part weight of solute in 1 million parts volume of solution. ppm…

Q: 1. You have a stock solution of 14.2 M NH3. How many milliliters of this solution should you dilute…

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Q: What volume of a 1.00 M stock solution of glucose must be used to make 500.0 mL of a 1.75 x 10-2 M…

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Q: How many grams of KOH are present in 35.0 ml of 5.50 M solution? Atomic Masses:K = 39.10; 0 = 16.00;…

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Q: 1. A blood serum sample is analyzed and found to contain 102.5 µg Ca*/mL serum. The density of the…

A: 1. Here we will calculate concentration of Ca2+ with different unit. The density of the serum is…

Q: Help

A: Given, Initial molarity of stock solution, M1 = 2.50 M Final molarity of the solution, M2 = 1.25 M…

Q: You have a stock solution of 5.0 M NaCl. If you want to make 300.0 mL of 0.150 M NaCl, how many…

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Q: This lab used 6 M HCl that was diluted from a higher concentration.  If your lab instructor asked…

A: • Concentration (C) = No. of molesVolume• No. of moles = Concentration (C) x Volume (V)# If dilution…

Q: What volume of a stock solution of a 0.35 M Na2PO4 is needed to prepare 150 ml of a 0.2 M Na2PO4…

A: Given: Molarity of Na2PO4=0.35 M (Stock=M1) Volume=150 ml M2=0.2 M To find: Volume of stock solution…

Q: 'm trying to calculate the amount of sucrose in Cola. volume=50mL mass = 54.2060 g Density=…

A: Number of moles of sucrose is equal to the mass of sucrose divided by molar mass of sucrose.

Q: A 10.00 mL sample of 2.00 M Na3PO4 solution is diluted to a total volume of 150.0 mL. A sample of…

A: Given: Concentration of Na3PO4 stock solution = 2.00 M. Volume of Na3PO4 stock solution used = 10.00…

Q: A student made 10.0 mL of a 0.750 M solution in the following way. First, the student took some…

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Q: 1. A blood serum sample is analyzed and found to contain 102.5 ug Ca2*/mL serum: The density of the…

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Q: You have a standard stock 1.65 M solution of NaH2PO4. For an experiment you require 236 mL of a 0.82…

A: Given that -  Molarity of the stock NaH2PO4 Solution = 1.65 M  Molarity of diluted NaH2PO4 solution…

Q: True or false. A 3 gram of a substance that is classified as slightly soluble will dissolve in 200…

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Q: given a diluted acid solution that was tested by another student. They were supposed to make a…

A: Given: your experimental data matched the test but not the target concentration.

Q: A 21.8 mL solution of 14.2 M HCl is diluted to 228 mL. What is the new concentration of the acid…

A: Given : Initial concentration of HCl = 14.2 M Initial volume of solution = 21.8 mL And final volume…

Q: Describe how you would make a 500.0ml sample of 2.00 M KBr solution. You have access to solid KBr, a…

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Q: A simple equation that can be used ONLY for dilutions is M1V1 = M2V2.  So if a concentrated solution…

A: Given,M1= 1.36 MM2 = 0.286 M V2 = 50.0 mL

Q: Celery stalks that are immersed in fresh water for several hours become stiff. Similar stalks left…

A: Answer - Celery stalks that are immersed in fresh water for several hours become stiff. Similar…

Q: How much solid NaCl is needed to prepare 10.0 mL of a 0.100 M NaCl solution? mass of solid NaCI =…

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Q: You have stock solutions of 2.0 M copper sulfate and 5 M NaCl. You want to prepare a solution with a…

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Q: 3. If a researcher starts with 3.00 mL of a 4.50 mg/mL protein solution and adds 10.0 mL of water,…

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Q: Suppose you are working with a NaOH stock solution but you need a solution with a lower…

A: Given that :-   1.100 M stock NaOH  250.0 mL dilute NaOH solution 0.1230 M dilute NaOH solution.

Q: If you add 4.00 mL of pure water to 6.00 mL of 0.750 M NaCl solution, what is the concentration of…

A: Given, Volume of water = 4.00mL. Volume of NaCl solution = 6.00mL. Molarity of NaCl solution =…

Q: The volume of a 1.00 M HCl solution must be diluted to obtain 200 mL of a 0.250 M HC1 solution is…

A: The Volume of 1.00 M HCl solution after dilution can be calculated as follows: M1V1 = M2V2

Q: You wish to make a 0.350 M hydroiodic acid solution from a stock solution of 6.00 M hydroiodic acid.…

A: From the V1S1= V2S2 we can calculate it .

Q: You have 6.79 mL of  a 0.415 M aqueous solution of Sodium Bicarbonate (NaHCO3). You add all of this…

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