In the presence of aqueous cyanide, cadmium(II) ions will form the complex Cd(CN)42-. Determine the molar concentration of free uncomplexed cadmium(II) ion in the solution when 47.3g of Cd(NO3)2 is dissolved in exactly one litter of 2.0M sodium cyanide.  Kf of Cd(CN)42- at 25 degrees C is 7.2x1016

Q: Consider the following complex ion: [Cu(NH3)4]2+ Calculate the concentration of free, uncomplexed…

A: Given: Initial concentration of Cu2+ ions = 1.0 X 10-3 M = 0.001 M  And equilibrium concentration of…

Q: Silver and ammonia may react to form Ag(NH₃)₂⁺ complex (Kf = 1.66 x 107). A 500 mL of 0.20mol Ag⁺…

A: “Since you have posted a question with multiple sub-parts, we will solve first three subparts for…

Q: Pbl, solid (Kps = 9.8 x 10-9) is placed in a beaker with water. After some time, the concentration…

A:

Q: To form the complex ion [Cu(NH3)4]²+, you add CuCl to 1 M NH3 (Ksp of CuCl is 1.9 x 10-7). Calculate…

A: In such type of questions first write down solubility equilibrium of CuCl and formation equilibrium…

Q: What is the oxidation number of the central metal ion in each of the following complexes or…

A: Ans. (+2,+3,+1)

Q: at 25 °C. For the aqueous [Fe(CN)6]* complex K,=1.0 × 1035. 2+ jon. Suppose equal volumes of 0.0048…

A: After mixing the equal volumes of solutions, volume will be doubled and molarities or the…

Q: The fictitious complex M(SCN)2 can be produced from an aqueous equilibrium in which the M2+ ion is…

A: Since the reaction taking place will be  M2+ + 2 SCN- ----> M(SCN)2  hence from the above…

Q: For the aqueous [Cu(NH3)4 ] 2+ complex kf =5.6 x1011 at25°C .Suppose equal volumes of 0.0062M…

A: The equilibrium concentration of copper ion is calculated as,

Q: (Q61) Platinum cations in solution readily form complexes with free chloride anions in solution…

A: Given :  Kf = 1.0 x 1016  Initial [Pt+2] = 0.0127 M  [NaCl] = [Cl-] = 0.419 M

Q: n aqueous solution, the solubility of the alkali metal ions is given as follows: Li ˂ Na ˂ Rb˂Cs.…

A: For the solubility of alkali metals  depends on two parameters  1. Hydration energy  2. Lattice…

Q: When you perform the Beer’s Law analysis of Fe (SCN)2+, it is assumed that the complex concentration…

A: BEER'S LAW: The concentration of a substance present in a solution is equivalent and directly…

Q: A complex M(SCN)2 can be produced from an aqueous equilibrium in which the M2+ ion is mixed with…

A: Initial concentration of M+2 = 0.0001 M and SCN- = 0.00025 M, equilibrium concentration of M (SCN) 2…

Q: A 0.0300 M solution in Ni (N03) 2 and 0.15 M in the cyanide anion (CN-) is prepared. Ni2 + and CN-…

A: So to find out whether there will be any precipitate forming or not, we need to find the…

Q: Consider the formation of Ni(en)3]2+ from Ni(H20)6]+. The stepwise AG values at 298 K are AG1 for…

A:

Q: Are the complex ions [FeF6]3- and [HgF6]4- stable or not? Explain

A: Two complex ions which are to be determined for their stability.

Q: For the aqueous AlF63− complex =Kf×6.921019 at 25°C . Suppose equal volumes of…

A: We have given  Kf for [AlF6]3- = 6.92×1019      at 25°C  Concentration of Al(NO3)3 = 0.0096 M…

Q: Fe(NO3)3 (0.00100 mol) and KSCN (0.200 mol) are added to water to make exactly 1 liter of solution.…

A: The ICE table can be drawn as follows-

Q: Crystals of hydrated chromium(III) chloride are green, have an empirical formula of CrCl3 . 6 H2O,…

A: In the compound, the complex ion is shown below.

Q: Calculate the solubility product of lead(II) Phosphate (solubility= 0.00014g/L). a. What is the Ksp…

A: Given that solubility of lead (II) phosphate is 0.00014 g/L We have to find the solubility…

Q: Zinc(II)

A:

Q: For the aqueous [Hgl, complex K,= 6.76 x 1029 at 25 °C. Suppose equal volumes of 0.0098 M Hg(NO,)…

A: After mixing equal volume of Hg(NO3)2 and KIConcentration of Hg(NO3)2 = 0.0098 M2 = 0.0049 M = [Hg2+…

Q: 500.0 mL of 0.020 M Mn(NO3)2 are mixed with 1.0 L of 1.0 M Na2C204. The oxalate ion, C2042-, acts as…

A:

Q: For the aqueous [Cd(CN), complex K,=7.7 x 10 at 25 °C. Suppose equal volumes of 0.0012M Cd(NO,),…

A:

Q: Ni(OH)2 is a slightly soluble salt. In presence of ammonia, Ni²+ can form the complex Ni(NH3)2+ with…

A:

Q: 20.60 Commercial silver-plating operations frequently use a solution containing the complex Ag(CN);…

A:

Q: For the aqueous Cu(NH,), complex K, = 2.09 x 10 at 25 °C. Suppose equal volumes of 0.0020 M Cu(NO,),…

A: Given: Concentration of Cu(NO3)2 = 0.0020 M Concentration of NH3 = 0.12 M And equal volume of both…

Q: Consider the insoluble compound nickel(II) hydroxide , Ni(OH)2 . The nickel ion also forms a complex…

A:

Q: For the aqueous | Hg(NH3).] complex K, = 1.8 × 10 at 25 °C. Suppose equal volumes of 0.0092 M…

A: Given data,Kf=1.8×1019Molarity of Hg(NO3)2=0.0092MMolarity of NH3=0.46M

Q: The cation M2+ reacts with NH3 to form a series of complex ions as follows: + NH3 = M(NH3)²+…

A: See the reaction Product from equation 1 has been used in equation 2 Means the formation of…

Q: For the aqueous [Hgl, complex K,6.76 x 10 at 25 "C. Suppose equal volumes of 0.0092M Hg(NO,),…

A: Given :  Kf = 6.76 x 1029  [Hg(NO3)2] = 0.0092 M  [NaI] = 0.20 M

Q: For the aqueous [Hg(NH3)4]2+ complex Kf=1.911019 at 25°C. Suppose equal volumes of 0.0090M HgNO32…

A:

Q: For the aqueous [Ag(CN)2]^-    complex Kf =3.0x10^20 at 25°C.Suppose equal volumes of 0.0068M AgNO3…

A: Let us assume that volume of AgNO3 = Volume of KCN =V L.So, number of moles of AgNO3 = (molarity of…

Q: The K, for (Cu(en),1* is much larger than the one for (Cu(NH,),]2+. This difference is primarily an…

A: In the complex [Cu(en)2]2+ the ligand ethylene diamine (en) is a chelating ligand (multi dentate…

Q: For the aqueous [HgCl4]2- complex Kf=5.0 x1015 at 25°C.Suppose equal volumes of 0.0074M Hg(NO3)2…

A: Given,Kf = 5.0 × 1015 at 25 oC0.0074M of Hg(NO3)2  solution and 0.84M of NaCl

Q: The free energy change for the formation of the complex ion AlF63− is -140 kJ at 25°C. What is the…

A:

Q: For the aqueous [Cu(NH3)4]^2+ complex =Kf=5.6x10^11 at 25°C.Suppose equal volumes of 0.0058M…

A: The overall formation constant for the reaction is shown in equation  (1) in which Kf is the overall…

Q: For the aqueous | Hg(NH;),J complex K, = 1.8 × 10159 at 25 °C. Suppose equal volumes of…

A:

Q: For the aqueous [Fe(CN)6] complex K₁=1.00 × 10³5 at 25 °C. Suppose equal volumes of 0.0078M Fe(NO3),…

A:

Q: For the aqueous [HgI4] complex K₁=6.76 × 10²⁹ at 25 °C. Suppose equal volumes of 0.0066M Hg(NO3),…

A:

Q: You have 10mL of an 8% aqueous solution of H2Cl6Pt. Calculate the molar concentration of the…

A: Given: Volume of solution = 10 mL Convert mL into L as follows. 1 mL = 0.001 L10 mL = 10 mL × 0.001…

Q: For the aqueous Cd(CN), complex K, = 6.03 x 108 at 25 °C. Suppose equal volumes of 0.0040M Cd(NO,,…

A: We have to predict the equilibrium concentration of aqueous cadmium ion.

Q: REASsighment/takeCovalentActivity.do?locator=assignment-take [References) Cu ions from copper(II)…

A: On heating, blue colour turns to yellow. This means tetra aquacopper complex(blue) transfered to…

Q: In the presence of aqueous cyanide, cadmium(II) ions will form the complex Cd(CN)42- . Determine the…

A: The equilibrium equation for formation Cd(CN)42-is given below.

Q: Silver and ammonia may react to form Ag(NH₃)₂⁺ complex (Kf = 1.66 x 107 ). A 500 mL of 0.20 mol Ag⁺…

A: (a) Silver (Ag) and ammonia (NH3) react with each other and form Ag(NH3)2+ complex. The complexation…

Q: Define a complex liquid

A: Define a complex lipid :

Q: In the presence of aqueous cyanide, cadmium(II) ions will form the complex Cd(CN)42- .Determine the…

A: The formation of Cd(CN)42- takes place as,                                      Cd2+ (aq) + 4 CN-…

Coordination Chemistry

It is a part of chemistry, in which the study of compounds that have central atoms surrounded by molecules or ions, known as ligand, is known as coordination chemistry.