Iodine is made by the following reaction 2NaIO3+5NaHSO3->3NaHSO4+2Na2SO4+H2O+I2a. Name the two reactants b. If you wish to prepare 1.00 kg of I2 what masses of NaIO3 and NaHSO3 are required? c. What is the theoretical yield of I2 if you mixed 15.0g of NaIO3 with 125 mL of .853 M NaHSO3?

Question
Asked Oct 4, 2019

Iodine is made by the following reaction 2NaIO3+5NaHSO3->3NaHSO4+2Na2SO4+H2O+I2

a. Name the two reactants 

b. If you wish to prepare 1.00 kg of I2 what masses of NaIO3 and NaHSO3 are required? 

c. What is the theoretical yield of I2 if you mixed 15.0g of NaIO3 with 125 mL of .853 M NaHSO3?

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Step 1

Two reactants that participate in a reaction are sodium iodate (NaIO3) and Sodium bisulfite (NaHSO3).

Step 2

The molar masses of I­2, NaHSO3, and NaIO3 are 253.81 g/mol, 104.06 g/mol, and 197.89 g/mol respectively. The number of moles of I2 in 1 kg or 1000 grams of I2 is calculated as follows. The number of moles of I2 in 1 kg or 1000 grams of I2 is 3.94 moles.

1000 g
Moles of 2253.81g mol"
3.94 moles
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1000 g Moles of 2253.81g mol" 3.94 moles

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Step 3

According to the given chemical reaction, for each mole of I2, 2 moles of NaIO3 and 5 moles of NaHSO3 are required. thus, the required amounts of NaHSO3 and NaIO3 to prepare 3.94 moles of I2 is calculated a...

"(NaI0 = 2x 3.94 moles
7.88 moles
(NaHSO25x 3.94 moles
- 19.70 moles
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"(NaI0 = 2x 3.94 moles 7.88 moles (NaHSO25x 3.94 moles - 19.70 moles

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