Asked Feb 7, 2020

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Question: What is the percent yeild of the nicke(II) coordination?

  • [Ni(H2O)6]Cl2 used = 6.140 g
  • [Ni(en)3]Cl2 produced = 7.001 g


  • mol of [Ni(H2O)6]Cl2
    • 6.140 g/237.67 g/mol = 0.0258 mol [Ni(H2O)6]Cl2
  • mol of [Ni(en)3]Cl2
    • 0.0258 mol [Ni(H2O)6]Cl2 x (1 mol [Ni(H2O)6]Cl2/1mol [Ni(en)3]Cl2) = 0.0258 mol
  • grams of [Ni(en)3]Cl2
    • 0.0258 mol x 309.89 g/mol = 8.00 g
  • % yield 
    • 7.001 g/8.00 g = 87.5%

Expert Answer

Step 1

The number of moles for a given chemical species refers to the ratio of mass of the species to that of its molar mass. The formula is shown below:

Chemistry homework question answer, step 1, image 1


Step 2

The percent yield in chemistry can be defined as the ratio of actual yield to the theoretical yield multiplied by 100%. The formula is as follows:

Chemistry homework question answer, step 2, image 1

Step 3

In the given problem, the mass of [Ni(H2O)6]Cl2 which has been used is given to be 6.140 g.

The molar  mass of [Ni(H2O)6]Cl2 is 237.65 g/mol.

The number of moles of [Ni(H2O)6]Cl2 can be calculated as follows:

Chemistry homework question answer, step 3, image 1


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