Question
Asked Oct 6, 2019
Isopropyl alcohol is mixed with water to produce a 33.0 % (v/v) alcohol solution.
How many milliliters of each component are present in 625 mL of this solution? Assume that volumes are additive.
alcohol:
water:
mL
mL
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Isopropyl alcohol is mixed with water to produce a 33.0 % (v/v) alcohol solution. How many milliliters of each component are present in 625 mL of this solution? Assume that volumes are additive. alcohol: water: mL mL help about us contact us terms of use privacy policy careers A N B

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Expert Answer

Step 1

Amount of isopropyl alcohol presen...

% of alcohol by volume = 33.0%
That is, 33 mL isopropyl alcohol in 100 mL solution
33 mL
Amount of isopropyl alcohol in 625 mL solution = 625 mL solutionx.
100 mL solution
= 206.25 mL
Hence, 206.25 mL of isopropyl alcohol is present.
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% of alcohol by volume = 33.0% That is, 33 mL isopropyl alcohol in 100 mL solution 33 mL Amount of isopropyl alcohol in 625 mL solution = 625 mL solutionx. 100 mL solution = 206.25 mL Hence, 206.25 mL of isopropyl alcohol is present.

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