It is a consequence of Newton's law of gravitation that near the surface of any planet, the distance D fallen by a rock in time t is given by D = ct2. That is, distance fallen is proportional to the square of the time, no matter what planet one may be on. But the value of c depends on the mass of the planet. For Earth, if time is measured in seconds and distance in feet, the value of c is 16. (a) Suppose a rock is falling near the surface of a planet. What is the comparison in distance fallen from 3 seconds to 12 seconds into the drop? (Hint: This question may be rephrased as follows: "If time increases by a factor of 4, by what factor will distance increase?")
It is a consequence of Newton's law of gravitation that near the surface of any planet, the distance D fallen by a rock in time t is given by D = ct2. That is, distance fallen is proportional to the square of the time, no matter what planet one may be on. But the value of c depends on the mass of the planet. For Earth, if time is measured in seconds and distance in feet, the value of c is 16. (a) Suppose a rock is falling near the surface of a planet. What is the comparison in distance fallen from 3 seconds to 12 seconds into the drop? (Hint: This question may be rephrased as follows: "If time increases by a factor of 4, by what factor will distance increase?")
Chapter3: Polynomial Functions
Section3.5: Mathematical Modeling And Variation
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It is a consequence of Newton's law of gravitation that near the surface of any planet, the distance D fallen by a rock in time t is given by D = ct2. That is, distance fallen is proportional to the square of the time, no matter what planet one may be on. But the value of c depends on the mass of the planet. For Earth, if time is measured in seconds and distance in feet, the value of c is 16.
(a) Suppose a rock is falling near the surface of a planet. What is the comparison in distance fallen from 3 seconds to 12 seconds into the drop? (Hint: This question may be rephrased as follows: "If time increases by a factor of 4, by what factor will distance increase?")
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