It the 1980s, it was generally believed that congenital abnormalities affected about 7% of a large nation's children. Some people believe that the increase in the number of chemicals in the environment has led to an increase in the incidence of abnormalities. A recent study examined 394 randomly selected children and found that 30 of them showed signs of an abnormality. Is this strong evidence that the risk has increased? (We consider P-value of around 5% to represent reasonable evidence.) Complete parts a through f. Assume the independence assumption is met. a) Write appropriate hypotheses. Let p be the proportion of children with genetic abnormalities. Choose the correct answer below. O A. Ho: p=0.0761 vs. HA: p>0.0761 OB. Ho: p=0.07 vs. HA: P = 0.07 OC. Ho: p=0.0761 vs. HA: P<0.0761 OD. Ho: p=0.07 vs. HA: P <0.07 E. Ho: p=0.07 vs. HA: p > 0.07 OF. Ho: p=0.0761 vs. HA: P# 0.0761 b) Check the necessary assumptions. Which of the following are satisfied? Select all that apply. A. The independence assumption is satisfied. B. There are more than 10 successes and 10 failures. c. Less than 10% of the population was sampled. D. The sample is random. c) Perform the mechanics of the test. What is the P-value? (Round to three decimal places as needed.) P-value=

A:

A: Given,            The figure is shown below :

A: It is provided that

A:

A:

A: The expected value of obtaining complete and accurate information about the state of nature before…

A: A.The p-value of 0.036 indicates that there is a significant difference among the treatments at any…

A: 36,68,78,84,91,47,69,79,85,92,53,72,79,85,92,59,76,79,86,92,60,77,79,86,94,65,77,79,87,96,65,78,80,8…

A: The complete table is              R         L         S        TotalH        140     240     400…

A: Given query is to simplify the expressions.

A: λ = 1.5 per week  P(X = x ) = e^-λ (λt)x / x! Where x = no of accidents  in a week As per above…

A: Given  In a random sample of 25 people, the mean commute time to work was 31.6 minutes and the…

A: ∫02∫x2x y2x dy dx  =∫02x∫x2x y2dy dx  =∫02xy33x2xdx  =∫02x3y3x2xdx  =∫02x3x3-x23dx  =∫02x3x3-x6dx

A:

A: Given463