itn eneeent/showtest.php?action=skip&to-16You wish to test the following claim (Ha) at a significance level of a0.05.H.:Pi P2H: Pi P2You obtain 35 successes in a sample of size n1514 from the first population. You obtain -0 successes in a sample of375 from the second population. For this test, you should NOT use the continuity correction, and you shouldS1ze 12use the normal distribution as an approximation for the binomial distribution.What is the test statistic for this sample?(Report answer accurate to three decimal places.)test statisticWhat is the p-value for this sample? (Report answer accurate to four decimal places.)P-valueThe p-value is..1ess than (or equal to) agreater than aThis test statistic leads to a decision to..reject the nullaccept the nullfail to reject the nullAs such, the final conclusion is that.hot the first nonulation proportion 1s not equal to the

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Asked Nov 25, 2019
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itn eneee
nt/showtest.php?action=skip&to-16
You wish to test the following claim (Ha) at a significance level of a
0.05.
H.:Pi P2
H: Pi P2
You obtain 35 successes in a sample of size n1
514 from the first population. You obtain -0 successes in a sample of
375 from the second population. For this test, you should NOT use the continuity correction, and you should
S1ze 12
use the normal distribution as an approximation for the binomial distribution.
What is the test statistic for this sample?
(Report answer accurate to three decimal places.)
test statistic
What is the p-value for this sample? (Report answer accurate to four decimal places.)
P-value
The p-value is..
1ess than (or equal to) a
greater than a
This test statistic leads to a decision to..
reject the null
accept the null
fail to reject the null
As such, the final conclusion is that.
hot the first nonulation proportion 1s not equal to the
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itn eneee nt/showtest.php?action=skip&to-16 You wish to test the following claim (Ha) at a significance level of a 0.05. H.:Pi P2 H: Pi P2 You obtain 35 successes in a sample of size n1 514 from the first population. You obtain -0 successes in a sample of 375 from the second population. For this test, you should NOT use the continuity correction, and you should S1ze 12 use the normal distribution as an approximation for the binomial distribution. What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic What is the p-value for this sample? (Report answer accurate to four decimal places.) P-value The p-value is.. 1ess than (or equal to) a greater than a This test statistic leads to a decision to.. reject the null accept the null fail to reject the null As such, the final conclusion is that. hot the first nonulation proportion 1s not equal to the

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Expert Answer

Step 1

Null Hypothesis:

 

H0:p1=p2

 

Alternative Hypothesis:

 

H1:p1p2

 

Test Statistic:

 

The test statistic is 5.152 and it is calculated below:

 

From the given information, there are 35 successes in a sample of n1=514 and there are 0 successes in a sample of n2=375. That is, x1=35, , x2=0,  n1=514 and n2=375.

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п 35 514 =0.068 р. п, 0 375 =0

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Step 2

The pooled sample proportion is,

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+x 35+0 514+375 =0.0394

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Step 3
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tst 1 p(1-p) n. 0.068-0 0.0394(1-0.0394) 514 375 0.068 0.0132 =5.152

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Hypothesis Testing

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