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Kiran drove from Tortula to Cactus, a distance of 300 mi. She increased her speed by 20 mi/h for the 400 mi trip from Cactus to Dry Junction. If the total trip took 10 h, what was her speed from Tortula to Cactus?

Question

Kiran drove from Tortula to Cactus, a distance of 300 mi. She increased her speed by 20 mi/h for the 400 mi trip from Cactus to Dry Junction. If the total trip took 10 h, what was her speed from Tortula to Cactus?

check_circleAnswer
Step 1

Given:

The distance from Tortula to Cactus is 300 mi and distance from Cactus to Dry Junction is 400 mi.

Kiran increases the speed by 20 mi/h. Total time for complete the trip is 10 h.

Step 2

Let the speed of vehicle from Tortula to Cactus be x ft/s.

Tabulate the given information into algebraic form.

Distance Speed
Time
Tortula to Cactus
300
300
х
х
Dry 400
400
Cactus
to
x+20
Junction
X +20
help_outline

Image Transcriptionclose

Distance Speed Time Tortula to Cactus 300 300 х х Dry 400 400 Cactus to x+20 Junction X +20

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Step 3

Model the equation for the...

time from Cactus to
time from Tortula
total time
+
to Cactus
Dry Junction
300
400
= 10
x+ 20
х
help_outline

Image Transcriptionclose

time from Cactus to time from Tortula total time + to Cactus Dry Junction 300 400 = 10 x+ 20 х

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