In the arrangement as shown, an object of mass m = 5.00 kg hangs from a cord around a light pulley. The length of the cord between point P and the pulley is L = 2.00 m. (a) When the vibrator is set to a frequency of 150 Hz, a standing wave with six loops is formed. What must be the linear mass density of the cord? (b) How many loops (if any) will result if m is changed to 45.0 kg? (c) How many loops (if any) will result if m is changed to 10.0 kg?
The mass of the object,
The length of the chord,
The frequency of the vibrator,
The number of loops,
The expression for the frequency of the vibrator of the stretched string,
Rearrange the above equation for the linear mass density,
Substitute,
Therefore, the linear mass density of the chord is 0.0049 kg/m.
The mass of the object,
The length of the chord,
The frequency of the vibrator,
The linear mass density,
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