LD50 is the exposure at which half of a population will die. Look at the LD50 for theNaCl oral dose for rats and express it as a percent. Use this percent to find out howmany pounds of salt would kill half the population of giant rats weighing 165 pounds(the weight of an average person).UD50 TeCratV101/4

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Asked Aug 27, 2019
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LD50 is the exposure at which half of a population will die. Look at the LD50 for the
NaCl oral dose for rats and express it as a percent. Use this percent to find out how
many pounds of salt would kill half the population of giant rats weighing 165 pounds
(the weight of an average person).UD50 Te
Crat
V
10
1/4
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LD50 is the exposure at which half of a population will die. Look at the LD50 for the NaCl oral dose for rats and express it as a percent. Use this percent to find out how many pounds of salt would kill half the population of giant rats weighing 165 pounds (the weight of an average person).UD50 Te Crat V 10 1/4

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Expert Answer

Step 1

The exposure to LD50 leads to the death of half of the population. The LD50 oral dose required to kill the 50 % population of rats is 3.0 g/kg for sodium chloride which means 3.0 g of sodium chloride is required to kill the half of the population of rats weighing 1 kg.

 

This value can be converted into pounds as follows:

1.0 kg
0.002204 pounds
3.0 g/kg (3.0 g/kg)
2.204 pounds
1.0 g
= 3.0x 10
pounds/pound
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1.0 kg 0.002204 pounds 3.0 g/kg (3.0 g/kg) 2.204 pounds 1.0 g = 3.0x 10 pounds/pound

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Step 2

Multiply the weight of population with the LD50 dose of salt to calculate ...

Amount of NaCl = 3.0 x 10
pounds/pound x165 pound
-0.495 pounds
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Amount of NaCl = 3.0 x 10 pounds/pound x165 pound -0.495 pounds

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